php - 如何在 1 个查询中合并 3 个表

Question

我需要将 3 件事合并到 1 个查询中以在图表上表示它。

第一个查询是查找 NetAmount2017 第二个问题是寻找预算(2017) 第三个查询是查找 NetAmount2016

第一个查询:NetAmount2017

SELECT sum(a.netamt) as netamt2017, b.store_name 
FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
WHERE a.busidate >= '2017-01-01' AND a.busidate <='2017-04-30'
GROUP BY a.storenum

第二个查询:Budget2017

SELECT
SUM(CASE WHEN c.busidate BETWEEN '2017-01' AND '2017-04' THEN c.budget ELSE
0 END) as budget,
b.store_name
FROM site_kpimthslsbgt c JOIN site_store b ON b.storenum = c.storenum 
GROUP BY c.storenum

第三个查询:NetAmount2016(与第一个查询相同，但日期不同)

SELECT sum(a.netamt) as netamt2017, b.store_name 
FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
WHERE a.busidate >= '2016-01-01' AND a.busidate <='2016-04-30'
GROUP BY a.storenum

据我所知，我只能组合 2 个查询，不知道组合 3 个查询。这是我的 2017 年预算和 2017 年 Netty 的组合。

 Select x.netamt, y.budget, y.store_name
 from
 (
 SELECT sum(a.netamt) as netamt, b.store_name 
 FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
 WHERE a.busidate >= '2017-01-01' AND a.busidate <='2017-04-30'
 GROUP BY a.storenum
 ) x
 inner join
 (
 SELECT
 SUM(CASE WHEN c.busidate BETWEEN '2017-01' AND '2017-04' THEN c.budget 
 ELSE 0 END) as budget,
 b.store_name
 FROM site_kpimthslsbgt c JOIN site_store b ON b.storenum = c.storenum 
 GROUP BY c.storenum
 ) y
 on x.store_name = y.store_name

我想要的结果应该显示在 1 个图表中，该图表由 3 个条形图组成，分别是 Netamount2017、Budget2017 和 Netamount2016。下图显示了结果，但是2017年的预算只显示了1个月，而不是我选择的1月到4月的所选月份。这是我迄今为止得到的组合 3 个查询的查询

SELECT
SUM(CASE WHEN a.busidate BETWEEN '2016-01-01' AND '2016-04-30' THEN a.netamt 
ELSE 0 END) as netamt2016,
SUM(CASE WHEN a.busidate BETWEEN '2017-01-01' AND '2017-04-30' THEN a.netamt ELSE 0 
END) as netamt,
b.store_name,
c.budget
FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
JOIN site_kpimthslsbgt c ON b.storenum = c.storenum 
WHERE c.busidate = '2017-01' AND b.store_region='$store_region'
GROUP BY a.storenum

如果我执行下面的查询，如果给我错误的计算。

SELECT
SUM(CASE WHEN a.busidate BETWEEN '2016-01-01' AND '2016-04-30' THEN a.netamt 
ELSE 0 END) as netamt2016,
SUM(CASE WHEN a.busidate BETWEEN '2017-01-01' AND '2017-04-30' THEN a.netamt ELSE 0 
END) as netamt,
b.store_name,
c.budget
FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
JOIN site_kpimthslsbgt c ON b.storenum = c.storenum 
WHERE c.busidate BETWEEN '2017-01' AND '2017-04' AND b.store_region='$store_region'
GROUP BY a.storenum

Answer 1

感谢上帝!我找到了答案，将所有查询合并为 1 个查询。 这是代码:

 SELECT x.netamt2017,z.netamt2016, y.budget, y.store_name
 FROM
 (
 SELECT sum(a.netamt) as netamt2017, b.store_name 
 FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
 WHERE a.busidate >= '$date1' AND a.busidate <='$date2' AND 
 a.storenum='$storenum'
 GROUP BY a.storenum
 ) x

 inner join
 (
 SELECT
 SUM(CASE WHEN c.busidate BETWEEN '$date111' AND '$date211' THEN c.budget 
 ELSE 0 END) as budget,
 b.store_name
 FROM site_kpimthslsbgt c JOIN site_store b ON b.storenum = c.storenum 
 WHERE c.storenum='$storenum'
 GROUP BY c.storenum
 ) y
 on x.store_name = y.store_name
 INNER JOIN
 (
 SELECT sum(a.netamt) as netamt2016, b.store_name 
 FROM site_sales a JOIN site_store b ON b.storenum = a.storenum 
 WHERE a.busidate >= '$date1234' AND a.busidate <='$date2234' AND 
 a.storenum='$storenum'
 GROUP BY a.storenum
 ) z
 on y.store_name = z.store_name