php - 在php while循环中显示其他表的数据

Question

我正在尝试显示来自另一个表的选择标记中的选项，而我的 首先，当循环继续时，这是我到目前为止所尝试过的!!

<?php
     $query="SELECT * FROM `customerdata` WHERE takenby='$_SESSION[username]'";
     $query_two="SELECT * FROM `vendordriver` WHERE vendoremail='$_SESSION[username]'";
     $run_two=$db->query($query_two);
     $run=$db->query($query);
     while ($row=$run->fetch_assoc()) {
       echo " <tr><td>$row[bookingid]</td>
       <td>$row[drivername]</td>
       <td>$row[cabtype]</td>
       <td>$row[carnumber]</td><td><select>";
  while ($row_two=$run_two->fetch_assoc()) {
    echo "<option>$row_two[drivername]</option>";
  }
echo" </select></td>
       <td><input type='submit' class='btn btn-success' value='SEND '>
       </td>";
     }
    ?>

请提出任何建议!!!

Answer 1

您可以尝试此代码

<?php
$table_1 = null;
$username = $_SESSION['username'];
$query="SELECT * FROM customerdata WHERE takenby='$username'";
$run=$db->query($query);
if ($result->num_rows > 0) {
    while ($row=$run->fetch_assoc()) {
    $table_1 = "<tr><td>$row[bookingid]</td>";
    $table_1 .= "<td>$row[drivername]</td>";
    $table_1 .= "<td>$row[cabtype]</td>";
    $table_1 .= "<td>$row[carnumber]</td><td><select>";

echo $table_1;
$query_two="SELECT * FROM vendordriver WHERE vendoremail='$username'";
$run_two=$db->query($query_two);
        while ($row_two=$run_two->fetch_assoc()) {
            echo "<option>$row_two[drivername]</option>";
        }

        echo" </select></td>
        <td><input type='submit' class='btn btn-success' value='SEND '>
        </td>";
    }
}
?>