php - 获取两列中具有相同值的行数据

Question

我尝试过这个: 这段代码:

$sql="SELECT DISTINCT t_no,cust_name
FROM menu_order
WHERE b_id IN (
    SELECT b_id,m_name
    FROM menu_order
    GROUP BY b_id
    HAVING COUNT(*) > 1
)";


$result = mysql_query($sql);
$row =  mysql_fetch_array($result);

     echo $row['t_no'];
     echo $row['cust_name'];
while ($row = mysql_fetch_assoc($result, MYSQL_ASSOC)) {

    $name = $row['m_name'];
    $n = explode(',', $name);
    foreach ($n as $d) {
        if ($d !== '') { // because before first comma or after last can be empty
            echo $d.",".PHP_EOL;

        }

    }

}

请问谁能告诉我如何在php中使用t_no(table number)来获取数据。 这里，b_id(booking_id) 是外键。

预期输出:

1    |T03  | 2017-08-07 | Dal Fry,Sahi Paneer,Aloo Paratha | 2,1,1

Here is the database:

Answer 1

您可以将GROUP BY与GROUP_CONCAT一起使用，例如:

SELECT b_id, t_no, date, GROUP_CONCAT(m_name), GROUP_CONCAT(quantity)
FROM table
GROUP BY b_id, t_no, date;

Here's MySQL 的 GROUP_CONCAT() 函数文档。