java - 为什么我的 'userID' 初始化为 0 而不是从 PHP 发送的内容？

Question

我试图将 PHP 后端中标记为“sno”的 userId 放入共享首选项中，然后在尝试根据该用户的 userID 加载帖子时从共享首选项中检索 userId。调试器中的 userId 显示为“0”。但根据调试器，所有其他信息(例如电子邮件名称和唯一 ID)都很好。

这是我的登录过程的请求对象，该过程应该将用户 ID 存储在首选项中。

RequestInterface requestInterface =             retrofit.create(RequestInterface.class);
        User user = new User();
        user.setEmail(email);
        user.setPassword(password);
        ServerRequest request = new ServerRequest();
        request.setOperation(Constants.LOGIN_OPERATION);
        request.setUser(user);
        Call<ServerResponse> response =    requestInterface.operation(request);
        response.enqueue(new Callback<ServerResponse>() {
        @Override
        public void onResponse(Call<ServerResponse> call, retrofit2.Response<ServerResponse> response) {
            ServerResponse resp = response.body();
            Snackbar.make(getView(), resp.getMessage(), Snackbar.LENGTH_LONG).show();
            if(resp.getResult().equals(Constants.SUCCESS)){
                SharedPreferences.Editor editor = pref.edit();
                editor.putBoolean(Constants.IS_LOGGED_IN,true);                     editor.putString(Constants.EMAIL,resp.getUser().getEmail());                    editor.putString(Constants.NAME,resp.getUser().getName());                    editor.putString(Constants.UNIQUE_ID,resp.getUser().getUnique_id());
                editor.putInt(Constants.USER_ID, resp.getUser().getUserID());
                editor.apply();
                goToAllPosts();
           }
            progress.setVisibility(View.INVISIBLE);
        }

这是我的用户类: 公共(public)类用户{

private String name;
private String email;
private String unique_id;
private String password;
private String old_password;
private String new_password;
private int userID;
private List<Post> allPostsList;
public List<Post> getAllPosts(){
    return allPostsList;
}
public void setAllPosts(List<Post> allPostsList){
this.allPostsList = allPostsList;
}
public String getName() {
    return name;
}
public String getEmail() {
    return email;
}
public String getUnique_id() {
    return unique_id;
}
public int getUserID(){
    return userID;
}
public int setUserID(int userID) { return this.userID = userID;}
public void setName(String name) {
    this.name = name;
}
public void setEmail(String email) {
    this.email = email;
}
public void setPassword(String password) {
    this.password = password;
}
public void setOld_password(String old_password) {
    this.old_password = old_password;
}
public void setNew_password(String new_password) {
    this.new_password = new_password;
}
}

这是我的相关 php: 索引.php:

if ($operation == 'login') {
    if(isset($data -> user ) && !empty($data -> user) && isset($data ->       user -> email) && isset($data -> user -> password)){
      $user = $data -> user;
      $email = $user -> email;
      $password = $user -> password;
      echo $fun -> loginUser($email, $password);
    } else {
      echo $fun -> getMsgInvalidParam();
    }

函数.php:

public function loginUser($email, $password) {
$db = $this -> db;
if (!empty($email) && !empty($password)) {
if ($db -> checkUserExist($email)) {
   $result =  $db -> checkLogin($email, $password);
   if(!$result) {
    $response["result"] = "failure";
    $response["message"] = "Invaild Login Credentials";
    return json_encode($response);
   } else {
    $response["result"] = "success";
    $response["message"] = "Login Successful";
    $response["user"] = $result;
    return json_encode($response);
   }
} else {
  $response["result"] = "failure";
  $response["message"] = "Invaild Login Credentials";
  return json_encode($response);
}
} else {
  return $this -> getMsgParamNotEmpty();
}
}

DBOperations.php:

public function checkLogin($email, $password) {
$sql = 'SELECT * FROM users WHERE email = :email';
$query = $this -> conn -> prepare($sql);
$query -> execute(array(':email' => $email));
$data = $query -> fetchObject();
$salt = $data -> salt;
$db_encrypted_password = $data -> encrypted_password;
if ($this -> verifyHash($password.$salt,$db_encrypted_password) ) {
    $user["name"] = $data -> name;
    $user["email"] = $data -> email;
    $user["unique_id"] = $data -> unique_id;
            $user["sno"] = $data -> sno;
    return $user;
} else {
    return false;
}
}
public function checkUserExist($email){
$sql = 'SELECT COUNT(*) from users WHERE email =:email';
$query = $this -> conn -> prepare($sql);
$query -> execute(array('email' => $email));
if($query){
    $row_count = $query -> fetchColumn();
    if ($row_count == 0){
        return false;
    } else {
        return true;
    }
} else {
    return false;
}
}

如果我没有包含一些必要的建议，请告诉我，我可以发布它。 提前致谢

Answer 1

User.userID 持有 0，因为 0 是 int 的默认值，并且是一个真实值无法从您的网络响应中反序列化。仔细检查您的服务器响应是否使用 "userID" 作为保存此 ID 的字段名称，而不是类似 "user_id" 的名称。