php - 排除 foreach 表中的列而不丢失数据

Question

我需要阻止 ID 列显示在 html/php 生成的 foreach 表中，但同时我仍然需要引用要按 ID 编辑的数据。这是代码。

$queryz = "SELECT * FROM box WHERE date=CURDATE()";

    print "<table> ";
    $result = mysqli_query($db,$queryz);
    //return only the first row (we only need field names)
    $row = $result->fetch_assoc();  
    print " <tr> ";
    foreach ($row as $field => $value){
    print " <th>$field</th> ";
    } // end foreach
    print " </tr> ";
    //second query gets the data
    $data = $result;
    $data->fetch_assoc();
    foreach($data as $row){
    print " <tr> ";
    foreach ($row as $name=>$value){
    print " <td>$value</td> ";

    } // end field loop
    echo '<td><a href="edit.php?id=' . $row['ID'] . '">Edit</a></td>';
    echo '<td><a href="print.php?id=' . $row['ID'] . '">Print</a></td>';
    print " </tr> ";
    } // end record loop

我希望它抓取所有列，但不显示 ID 列。我仍然需要 ID 数据，以便可以编辑表格:echo '<td><a href="edit.php?id=' . $row['ID'] . '">Edit</a></td>';

谢谢大家!我尝试过通过 if 数组进行过滤并排除 SQL 中的数据，但它不允许我随后编辑表。我猜测是因为它一开始就没有抓取数据。

Answer 1

您可以通过简单地忽略键为“ID”的数组项来解决眼前的问题，如下所示:

$queryz = "SELECT * FROM box WHERE date=CURDATE()";

print "<table> ";
$result = mysqli_query($db,$queryz);

//return only the first row (we only need field names)
$row = $result->fetch_assoc();  

print " <tr> ";
foreach ($row as $field => $value){
  if ( $field <> 'ID' ) {
    print " <th>$field</th> ";      
  }
} // end foreach
print " </tr> ";

//second query gets the data
$data = $result;
$data->fetch_assoc();

foreach($data as $row) {
  print " <tr> ";
  foreach ($row as $name=>$value){
    if ( $name <> 'ID' ) {
      print " <td>$value</td> ";
    }
  } // end field loop
  echo '<td><a href="edit.php?id=' . $row['ID'] . '">Edit</a></td>';
  echo '<td><a href="print.php?id=' . $row['ID'] . '">Print</a></td>';
  print " </tr> ";
} // end record loop