mysql - Spring Data JPA - 为类提供了错误类型的 id。应为 : class java. lang.Integer，得到类 java.lang.Long

Question

我在使用 Spring JPA 并尝试检索对象列表时遇到此问题。

这是我要检索的类

@Entity
@Table(name="OBJECTSTERMIC")
public class TermicObject {

    @Id
    @Column(name="TERMICID")
    private long termicId;

    @MapsId
    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="OBJECTID",columnDefinition="INTEGER")
    private Object object;

    @Column(name="CONTECA_RIF")
    private int contecaRif;

    @Column(name="CONTECA_VAL")
    private int contecaVal;

    @Column(name="TYPE")
    private String type;

//getters and setters

Object 类在 MySQL 上将主键存储为 Integer，这确实是 Object

@Entity
public class Object {

    @Column(name="OBJECTID")
    @Id
    @JsonProperty("OBJECTID")
    private int objectId;
    ....

所以，没有地方设置 Long...

现在，我只需调用一个服务类

@Override
    public List<TermicObject> findAll() {

        return repository.findAll();
    }

并得到这个异常

org.springframework.dao.InvalidDataAccessApiUsageException: org.hibernate.TypeMismatchException: Provided id of the wrong type for class it.besmart.db_eipo.persistence.model.Object. Expected: class java.lang.Integer, got class java.lang.Long; nested exception is java.lang.IllegalArgumentException: org.hibernate.TypeMismatchException: Provided id of the wrong type for class it.besmart.db_eipo.persistence.model.Object. Expected: class java.lang.Integer, got class java.lang.Long

在哪里设置Object Id应该是Long？

Answer 1

查看您的存储库的定义。它有正确的泛型类型吗？你有整数作为第二个参数吗？恕我直言，这可能是根本原因。查看建议的正确版本:

@RepositoryRestResource
public interface TermicObjectRepository extends JpaRepository<TermicObject, Integer> {
    public Optional<TermicObject> findById(Integer id);
    public List<TermicObject> findAll()
}