PHP:根据一个键上的组从 Json 数组创建多个 Json 数组

Question

我有一个如下所示的 JSON 数组:-

[{
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06",

}, {
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06",

}, {
    "order_no": "G1049",
    "contract_no": "DCI-37500029",
    "dc_in_date": "2017-11-06",

}]

我想创建数组数量，其中包含类似contract_no的所有键值对。对于上面的示例，我想要输出如下:-

数组-I

[{
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06",

}, {
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06",

}]

和

数组-II

[ {
    "order_no": "G1049",
    "contract_no": "DCI-37500029",
    "dc_in_date": "2017-11-06",

}]

基本想法是我有一个有两列的 Mysql 表。一种是“contract_no”，另一种是“order_details”。我想将 order_details 的值更新为契约(Contract)号匹配的 Array-I 和 Array-II。

有办法做到这一点吗？

Answer 1

您可以使用 array_search 和 array_column 方法。

<?php

function recursive_array_search($needle,$haystack) {
    $return = null;
    foreach($haystack as $key=>$value) {
        $current_key=$key;
        if($needle===$value || (is_array($value) && recursive_array_search($needle,$value) !== null)) {
            $return[] = $current_key;
        }
    }
    return $return;
}

$json = '[{
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06"
}, {
    "order_no": "1",
    "contract_no": "DCI-92700028",
    "dc_in_date": "2017-11-06"
}, {
    "order_no": "G1049",
    "contract_no": "DCI-37500029",
    "dc_in_date": "2017-11-06"
}]';
$array = json_decode($json, true);
echo '<pre>';
    print_r($array);
    echo '</pre>';
$columns = array_column($array,'contract_no');
foreach($columns as $column){
    echo 'Contact No:'.$column.'<br />';
    $found_key = recursive_array_search($column, $array);
    echo '<pre>';
    print_r($found_key);
    echo '</pre>';

}
?>