php - 如何将数组的元素更改为对象？

Question

我正在从具有不同列的表中获取数据，然后将其保存在数组中。这是我的代码:

$sql="SELECT image,image1,image2,image3,image4,image5 FROM `app_places` where place_id='".$place_id."'  ";
    $check= mysqli_query($conn, $sql);
    $rowcount=mysqli_num_rows($check);
    //var_dump($rowcount);
    if($rowcount<=0)
    {
        $minfo = array("success"=>'false',"msg"=>'invalid place_id');
        $jsondata = json_encode($minfo);
        print_r($jsondata);
        exit(); 

        }
        else
        {
            $data = array();
            while ($row = mysqli_fetch_array($check,MYSQLI_NUM))
            {
                $data[] = $row;
            }

我将其编码为 json 格式，我的输出如下:

{"allplaces":
[
{
"image":"http://www.freepngimg.com/download/lion/3-2-lion-png.png","image1":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png","image2":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png","image3":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png","image4":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png","image5":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"
}
]
}

但我需要这样:

     {"allplaces":[
    {"image":"http://www.freepngimg.com/download/lion/3-2-lion-png.png"},
{"image1":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"},

{"image2":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"},

{"image3":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"},

{"image4":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"},

{"image5":"http://mobileappdatabase.in/city/uploads/default-image/defaultimage.png"}]}

Answer 1

只有当您有 1 行时，这才有效。你的表结构很糟糕，但是你可以了。

while ($row = mysqli_fetch_array($check,MYSQLI_ASSOC)) {
    foreach($row as $key => $value){
     $data[] = array(
       $key => $value
     );
    }    
}