所以我试图将 JSP 表单中的记录注册(插入)到数据库(XAMPP、MySQL)中。详情如下:
注册.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action = "RegisterController" method = "post">
<input type = "text" name = "email" placeholder = "Your e-mail"><br><br>
<input type = "text" name = "firstname" placeholder = "First name"><br><br>
<input type = "text" name = "lastname" placeholder = "Last name"><br><br>
<input type = "text" name = "address" placeholder = "Home address"><br><br>
<input type = "text" name = "phone" placeholder = "Your phone number"><br><br>
<input type = "password" name = "password"><br><br>
<input type = "submit" name = "submit" value = "Register">
</form>
</body>
</html>
RegisterController.java
package cms.com;
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class RegisterController
*/
public class RegisterController extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public RegisterController() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try{
String email = request.getParameter("email");
String firstname = request.getParameter("firstname");
String lastname = request.getParameter("lastname");
String address = request.getParameter("address");
String phone = request.getParameter("phone");
String password = request.getParameter("password");
String sql = "insert into users(email,firstname,lastname,address,phone,password) values(?,?,?,?,?,?)";
Class.forName("com.mysql.jdbc.Driver");
Connection conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/cms","root","");
PreparedStatement pst = conn.prepareStatement(sql);
pst.setString(1,email);
pst.setString(2,firstname);
pst.setString(3,lastname);
pst.setString(4,address);
pst.setString(5, phone);
pst.setString(6, password);
pst.executeUpdate();
PrintWriter out = response.getWriter();
out.println("You have successfully registered!");
}
catch(ClassNotFoundException e){
e.printStackTrace();
}
catch(SQLException e){
e.printStackTrace();
}
}
}
因此，当我在本地主机上运行并输入详细信息时，它仅显示一个空页面，并且该表没有任何更新。调试以及在运行时期间都没有显示错误。我将 Eclipse Luna 与 Dynamic Module 2.5 和 Apache Tomcat 7.0 结合使用。
最佳答案
您必须添加Mysql jar 在您的项目中，并且您必须将 RegisterController 文件映射到 Web.xml 文件 (WebContent\WEB-INF\Web.xml)
并检查 Register.jsp 中“表单操作”的路径和 Web.xml 中“url-pattern”的路径，两者必须相同。
关于java - 使用 JSP (Eclipse) 将数据插入数据库(XAMPP、MySQL)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47842289/