java - JPA - 一对多合并问题

Question

当我尝试合并实体时，我面临下一个问题。

我有一个类菜单(一对多)-->类别(一对多)-->商品关联。

如果我首先保留带有空类别和商品列表的菜单，则菜单将正确保留。

现在，如果我将当前的保存菜单与一个类别和空的商品列表合并，则该类别可以很好地保存，即使我将一种新商品添加到空的商品列表中，这也可以很好地保存。

现在，如果我在商品列表中添加第二个商品，则会出现此错误:

Menu [menuId=1, menu_name=dsad, menu_description=null, categories=[Category [category_id=1, categoryName=a, goods=[GoodsImp [id=1, brand=asd, createdDate=Mon Jan 22 18:26:35 ART 2018], price =3.0, description=asd, type= product] ], GoodsImp [id=null, brand=dsad, createdDate=null], price=33333.0, description=sd, type= product] ]]], Category [category_id=2, categoryName=b, goods=[ ]]], business=2]

-------------- Hibernate:

/* load models.menu.Menu */ select
    menu0_.MENU_ID as MENU_ID1_7_1_,
    menu0_.BUSINESS_ID as BUSINESS2_7_1_,
    menu0_.MENU_DESCRIPTION as MENU_DES3_7_1_,
    menu0_.MENU_NAME as MENU_NAM4_7_1_,
    categories1_.Menu_MENU_ID as Menu_MEN1_8_3_,
    category2_.CATEGORY_ID as categori2_8_3_,
    category2_.CATEGORY_ID as CATEGORY1_2_0_,
    category2_.CATEGORY_NAME as CATEGORY2_2_0_
from
    MENUES menu0_
left outer join
    MENUES_CATEGORIES categories1_
        on menu0_.MENU_ID=categories1_.Menu_MENU_ID
left outer join
    Categories category2_
        on categories1_.categories_CATEGORY_ID=category2_.CATEGORY_ID
where
    menu0_.MENU_ID=? Hibernate:
/* load models.menu.Product */ select
    product0_.GOODS_ID as GOODS_ID2_6_0_,
    product0_.GOODS_BRAND as GOODS_BR3_6_0_,
    product0_.GOODS_CREATED as GOODS_CR4_6_0_,
    product0_.GOODS_DESCRIPTION as GOODS_DE5_6_0_,
    product0_.GOODS_IMAGE as GOODS_IM6_6_0_,
    product0_.GOODS_PRICE as GOODS_PR7_6_0_
from
    GOODS product0_
where
    product0_.GOODS_ID=?
    and product0_.DTYPE='PRODUCT'

hibernate :

/* insert models.menu.Product
    */ insert
    into
        GOODS
        (GOODS_BRAND, GOODS_CREATED, GOODS_DESCRIPTION, GOODS_IMAGE, GOODS_PRICE, DTYPE)
    values
        (?, ?, ?, ?, ?, 'PRODUCT') Hibernate:
select
    goods0_.GOODS_ID as GOODS_ID2_6_0_,
    goods0_.GOODS_ID as GOODS_ID2_6_1_,
    goods0_.GOODS_BRAND as GOODS_BR3_6_1_,
    goods0_.GOODS_CREATED as GOODS_CR4_6_1_,
    goods0_.GOODS_DESCRIPTION as GOODS_DE5_6_1_,
    goods0_.GOODS_IMAGE as GOODS_IM6_6_1_,
    goods0_.GOODS_PRICE as GOODS_PR7_6_1_,
    goods0_.GOODS_PRICE_TYPE as GOODS_PR8_6_1_,
    goods0_.DTYPE as DTYPE1_6_1_
from
    GOODS goods0_
where
    goods0_.GOODS_ID=? Hibernate:
select
    goods0_.GOODS_ID as GOODS_ID2_6_0_,
    goods0_.GOODS_ID as GOODS_ID2_6_1_,
    goods0_.GOODS_BRAND as GOODS_BR3_6_1_,
    goods0_.GOODS_CREATED as GOODS_CR4_6_1_,
    goods0_.GOODS_DESCRIPTION as GOODS_DE5_6_1_,
    goods0_.GOODS_IMAGE as GOODS_IM6_6_1_,
    goods0_.GOODS_PRICE as GOODS_PR7_6_1_,
    goods0_.GOODS_PRICE_TYPE as GOODS_PR8_6_1_,
    goods0_.DTYPE as DTYPE1_6_1_
from
    GOODS goods0_
where
    goods0_.GOODS_ID=? Hibernate:



   /* update  models.menu.Product */ update
        GOODS
    set
        GOODS_BRAND=?,
        GOODS_CREATED=?,
        GOODS_DESCRIPTION=?,
        GOODS_IMAGE=?,
        GOODS_PRICE=?
    where
        GOODS_ID=? Hibernate:
/* create one-to-many row models.menu.Category.goods */ update
    GOODS
set
    GOODS_ID=?
where
    GOODS_ID=? [warn] o.h.e.j.s.SqlExceptionHelper - SQL Error: 1062, SQLState: 23000 [error] o.h.e.j.s.SqlExceptionHelper - Duplicate

entry '1' for key 'PRIMARY' [error] application -

! @76lfn933p - Internal server error, for (PUT) [/menu] ->

play.api.http.HttpErrorHandlerExceptions$$anon$1: Execution exception[[PersistenceException: org.hibernate.exception.ConstraintViolationException: could not execute statement]] at play.api.http.HttpErrorHandlerExceptions$.throwableToUsefulException(HttpErrorHandler.scala:255) at play.api.http.DefaultHttpErrorHandler.onServerError(HttpErrorHandler.scala:182) at play.filters.cors.AbstractCORSPolicy$$anonfun$1.applyOrElse(AbstractCORSPolicy.scala:155) at play.filters.cors.AbstractCORSPolicy$$anonfun$1.applyOrElse(AbstractCORSPolicy.scala:153) at scala.concurrent.Future.$anonfun$recoverWith$1(Future.scala:412) at scala.concurrent.impl.Promise.$anonfun$transformWith$1(Promise.scala:37) at scala.concurrent.impl.CallbackRunnable.run(Promise.scala:60) at play.api.libs.streams.Execution$trampoline$.execute(Execution.scala:70) at scala.concurrent.impl.CallbackRunnable.executeWithValue(Promise.scala:68) at scala.concurrent.impl.Promise$DefaultPromise.$anonfun$tryComplete$1(Promise.scala:284) Caused by: javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: could not execute statement at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:149) at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:157) at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:164) at org.hibernate.internal.SessionImpl.doFlush(SessionImpl.java:1443) at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1423) at repository.JPAMenuesRepository.lambda$updateMenu$2(JPAMenuesRepository.java:46) at play.db.jpa.DefaultJPAApi.lambda$withTransaction$3(DefaultJPAApi.java:197) at play.db.jpa.DefaultJPAApi.withTransaction(DefaultJPAApi.java:138) at play.db.jpa.DefaultJPAApi.withTransaction(DefaultJPAApi.java:196) at play.db.jpa.DefaultJPAApi.withTransaction(DefaultJPAApi.java:169) Caused by: org.hibernate.exception.ConstraintViolationException: could not execute statement at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:59) at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:42) at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:111) at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:97) at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:178) at org.hibernate.engine.jdbc.batch.internal.NonBatchingBatch.addToBatch(NonBatchingBatch.java:45) at org.hibernate.persister.collection.AbstractCollectionPersister.insertRows(AbstractCollectionPersister.java:1567) at org.hibernate.persister.collection.OneToManyPersister.insertRows(OneToManyPersister.java:193) at org.hibernate.action.internal.CollectionUpdateAction.execute(CollectionUpdateAction.java:85) at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:589) Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Duplicate entry '1' for key 'PRIMARY' at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at com.mysql.jdbc.Util.handleNewInstance(Util.java:425) at com.mysql.jdbc.Util.getInstance(Util.java:408) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:936) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3973) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3909) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2527)

Answer 1

我可以修复它。

问题是，一对多关系有一个 @JoinColumn 而不是 @JoinTable。这就是当您编码几个小时时的问题，您只是看不到明显的东西。

谢谢大家。