我在 mysql 中使用三个表和一个查询来检索特定用户。
我从查询中得到了我想要的结果，但它的格式不正确。
我的查询:
public function get_all_payslips()
{
$empid = $this->session->userdata('EMPLOYEE_ID');
$orgid = $this->session->userdata('CURRENT_ORG_ID');
$where = "EMPLOYEE_ID ='".$empid."' ";
$response = array();
$queryString = "SELECT
em.EMPLOYEE_ID,
em.EMPLOYEE_NAME
FROM
uk_new_salary_slip assd,
employee_master em
WHERE
em.".$where."
GROUP BY em.EMPLOYEE_ID
order by em.EMPLOYEE_NAME asc";
$query = $this->db->query($queryString);
foreach ($query->result() as $data)
{
$result = array();
$result['EMPLOYEE_NAME'] = $data-> EMPLOYEE_NAME;
$queryString = "SELECT
mo.months,
MONTH((assd.pay_period)) as monthss,
YEAR((assd.pay_period)) as PAY_YEAR,
GROUP_CONCAT(DISTINCT(assd.id)) as action,
GROUP_CONCAT(DISTINCT(assd.ORG_ID)) as org
FROM
uk_new_salary_slip assd,
employee_master em,
months mo
WHERE
assd.emp_id = ". $data->EMPLOYEE_ID ."
AND mo.id = MONTH((assd.pay_period))
GROUP BY monthss,PAY_YEAR
order by PAY_YEAR desc";
$queryString1 = "SELECT
mo.months,
MONTH((germany.pay_from)) as monthss,
YEAR((germany.pay_from)) as PAY_YEAR,
GROUP_CONCAT(DISTINCT(germany.id)) as action,
GROUP_CONCAT(DISTINCT(germany.ORG_ID)) as org
FROM
new_germany_salary_slip germany,
employee_master em,
months mo
WHERE
germany.emp_id = ". $data->EMPLOYEE_ID ."
AND mo.id = MONTH((germany.pay_from))
GROUP BY monthss,PAY_YEAR
order by PAY_YEAR desc";
$queryString2 = "SELECT
mo.months,
MONTH((poland.pay_from)) as monthss,
YEAR((poland.pay_from)) as PAY_YEAR,
GROUP_CONCAT(DISTINCT(poland.id)) as action,
GROUP_CONCAT(DISTINCT(poland.ORG_ID)) as org
FROM
new_poland_salary_slip poland,
employee_master em,
months mo
WHERE
poland.emp_id = ". $data->EMPLOYEE_ID ."
AND mo.id = MONTH((poland.pay_from))
GROUP BY monthss,PAY_YEAR
order by PAY_YEAR desc";
$query1 = $this->db->query($queryString);
$query2 = $this->db->query($queryString1);
$query3 = $this->db->query($queryString2);
$children = array();
foreach ($query1->result() as $data1)
{
$yearArray = array();
$yearArray['month'] = $data1->months;
$yearArray['year'] = $data1->PAY_YEAR;
$yearArray['org'] = $data1->org;
$yearArray['action'] = $data1->action;
array_push($children, $yearArray);
}
foreach ($query2->result() as $data2)
{
$yearArray = array();
$yearArray['month'] = $data2->months;
$yearArray['year'] = $data2->PAY_YEAR;
$yearArray['org'] = $data2->org;
$yearArray['action'] = $data2->action;
array_push($children, $yearArray);
}
foreach ($query3->result() as $data3)
{
$yearArray = array();
$yearArray['month'] = $data3->months;
$yearArray['year'] = $data3->PAY_YEAR;
$yearArray['org'] = $data3->org;
$yearArray['action'] = $data3->action;
array_push($children, $yearArray);
}
$result['children'] = $children;
array_push($response, $result);
}
return $response;
}
如果在 month数组 year与 IN action 相同值应该是 4,2 。如果您在对象中看到第 0 个和第 4 个月份和年份相同，那么两个对象的 action值应该在一行中，类似地它的 org值应该是 org:40,47分别。
{month:"FEBRUARY", year:"2018",org:"40,47",action:"4,2"}
我希望数据的格式如下，但在我的例子中，它为每个操作显示不同的行。
最佳答案
数组推送只是将元素添加到数组的末尾。这不是你想要的。您想要本质上复契约(Contract)一年和同一月的元素。为此，我们可以将其指定为第一个子数组键，并将数组值简单地附加到 org 和 action:
$output = array();
foreach ($query1->result() as $data1) {
$key = $data1->PAY_YEAR . $data1->months;
if (!isset($output[$key]['month'])) {
$output[$key]['month'] = $data1->months;
$output[$key]['year'] = $data1->PAY_YEAR;
}
$output[$key]['org'][] = $data1->org;
$output[$key]['action'][] = $data1->action;
}
foreach ($query2->result() as $data2) {
$key = $data2->PAY_YEAR . $data2->months;
if (!isset($output[$key]['month'])) {
$output[$key]['month'] = $data2->months;
$output[$key]['year'] = $data2->PAY_YEAR;
}
$output[$key]['org'][] = $data2->org;
$output[$key]['action'][] = $data2->action;
}
foreach ($query3->result() as $data3) {
$key = $data3->PAY_YEAR . $data3->months;
if (!isset($output[$key]['month'])) {
$output[$key]['month'] = $data3->months;
$output[$key]['year'] = $data3->PAY_YEAR;
}
$output[$key]['org'][] = $data3->org;
$output[$key]['action'][] = $data3->action;
}
echo '<pre>';
print_r(array_keys($output));
关于php - 如何在php中使用mysql查询多维数组？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/48892948/