php - 使用 session 变量获取当前用户 ID

Question

下面的代码打印当前用户的正确用户 ID，但仅将 0 或 1 存储到

数据库。我不明白代码的问题。我们将非常感谢您的帮助

<?php  
 $user_id=print_r($_SESSION["id"]);

      if(isset($_POST['submit'])){ 

          $host = "";
          $db_name = "";
          $username = "";
          $password = "";

          $link=mysqli_connect($host, $username, $password, $db_name);

          //filename as image_path
          $filename=$_FILES['file']['name'];
          $filetmp=$_FILES['file']['tmp_name'];
          $image_title=$_POST['text'];
          $target="uploaded/".$filename;

          $date_time = date('Y-m-d H:i:s');
          $image_url="http://.....".$filename;

              if($filename!=""){

                  $sql="INSERT INTO images (image_path,created,image_url,image_title,user_id) VALUES('$filename','$date_time','$image_url','$image_title','$user_id')";
                  mysqli_query($link,$sql);

                   if(move_uploaded_file($filetmp,$target)){

                       echo "Image uploaded Successfully";

                   }
                   else{

                        echo "Failed to upload !!";
                   }

              }else{

                   echo "Please insert a valid image !!";
              }
      }
 ?>

Answer 1

您正在 $_SESSION["id"] 上使用 print_r，因此预计 $_SESSION["id"] 是一个数组，请尝试使用: $user_id = $_SESSION["id"];

或

echo $_SESSION["id"] 

打印