mysql - 按当前列和时间计算行数

Question

我的查询有问题。我想计算特定时间特定列中特定短语的出现次数。

这是我的 table :

CREATE TABLE `table` (
  `id` int(11) NOT NULL,
  `prodId` int(11) NOT NULL,
  `bookingAt` datetime NOT NULL,
  `equipmentType` varchar(30) NOT NULL,
  `shippingAt` datetime DEFAULT NULL
)

我有一个正在检查库存收据数量的有效查询:

SELECT g1.equipmentType,COUNT(*) as count FROM table g1
WHERE g1.shippingAt IS NULL AND 
g1.bookingAt BETWEEN :from AND :to GROUP BY g1.equipmentType

但我不知道如何构建已发送产品的查询:( 表中的示例数据:

INSERT INTO `table` (`id`, `prodId`, `bookingAt`, `equipmentType`, `shippingAt`) VALUES
(1, 9911199, '2018-04-05 09:30:03', 'Type1','2018-04-05 14:00:00'),
(2, 9911100, '2018-04-05 08:00:00', 'Type1','2018-04-05 14:10:00'),
(3, 1234563, '2018-04-05 10:05:40', 'Type2', NULL);

我的查询的工作结果(预订):

array [
  0 => array [
    "equipmentType" => "Type2"
    "count" => "1"
  ]

预期结果(发货):

array [
  0 => array [
    "equipmentType" => "Type1"
    "count" => "2"
  ]

Answer 1

在 ShippingAt 上的 NULL 测试中添加“NOT”将为您提供已发货的产品。

SELECT g1.equipmentType,COUNT(*) as count 
FROM table g1
WHERE g1.shippingAt IS NOT NULL 
AND g1.bookingAt BETWEEN :from AND :to 
GROUP BY g1.equipmentType;

此查询基于您提供的表格和数据，但它与标题或您在问题开始时询问的内容有何关系是一个谜。