我尝试在数据库中编辑我的数据，但它崩溃了并说我的变量未定义。输入命令 isset($_POST) 后，我的数据未在数据库中编辑，并显示消息“未更新”。 这是我的编辑文件:
<?php
// connect to the database
include('mysql_connect.php');
// get results from database
$result = mysqli_query($conn,"SELECT * FROM products")
or die(mysqli_error());
?>
<html>
<head>
<title>Update Data</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.1/css/bootstrap.min.css" >
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.1/js/bootstrap.min.js"></script>
</head>
<body>
<h1>Product list update</h1>
<hr>
<table style=" width:'50%'!important " class='table'>
<tr bgcolor='#CCCCCC'>
// Table
<th>SKU</th>
<th>Name</th>
<th>Price</th>
<th>Type</th>
<th>Details</th>
</tr>
<?php
while ($res = mysqli_fetch_array($result)){
echo "<tr><form action=update.php method=post>";
echo "<td><input type=text name=sku_p value='".$res['sku_product']."'></td>";
echo "<td><input type=text name=name_p value='".$res['name_product']."'></td>";
echo "<td><input type=text name=price_p value='".$res['price_product']."'></td>";
echo "<td><input type=text name=type_p value='".$res['type_product']."'></td>";
echo "<td>
Size for DVD: <input type=text name=sizedvd_p value='".$res['sizedvd_product']."'><br>
Weight for Book: <input type=text name=weightbook_p value='".$res['weightbook_product']."'><br>
For Furniture<br>
H: <input type=text name=heightfurn_p value='".$res['heightfurn_product']."'><br>
W: <input type=text name=widthfurn_p value='".$res['widthfurn_product']."'><br>
L: <input type=text name=lengthfurn_p value='".$res['lengthfurn_product']."'><br></td>";
echo "<input type=hidden name=id_p value='".$res['id_product']."'>";
echo "</form></tr>";
}
?>
<a href="index.php">Home</a><br>
<a href="update.php"><input type="submit" name="update" value="Submit"></a>
</table>
</body>
</html>
这是 update.php 文件，无法将我的数据更新到数据库
<?php
// connect to the database
$conn = mysqli_connect('localhost', 'root', '');
//Select DB
mysqli_select_db($conn, 'product_list');
// Update (in this case i have problems, which can't give an opportunity to change data in DB)
if(isset($_POST['update'])){
$result = mysqli_query($conn, "UPDATE products SET name_product='$_POST[name_p]', price_product='$_POST[price_p]', sku_product='$_POST[sku_p]', type_product='$_POST[type_p]',
sizedvd_product='$_POST[sizedvd_p]', weightbook_product='$_POST[weightbook_p]', heightfurn_product='$_POST[heightfurn_p]', widthfurn_product='$_POST[widthfurn_p]', lengthfurn_product='$_POST[lengthfurn_p]'
WHERE id_product='$_POST[id_p]' ");
}
echo "Not Update";
?>
最佳答案
尝试下面的代码，看看它是否有效。让我知道您遇到了什么错误。
<?php
// connect to the database
include('mysql_connect.php');
// get results from database
$result = mysqli_query($conn,"SELECT * FROM products");
or die(mysqli_error());
?>
<html>
<head>
<title>Update Data</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.1/css/bootstrap.min.css" >
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.1/js/bootstrap.min.js"></script>
</head>
<body>
<h1>Product list update</h1>
<hr>
<table style=" width:'50%'!important " class='table'>
<tr bgcolor='#CCCCCC'>
<th>SKU</th>
<th>Name</th>
<th>Price</th>
<th>Type</th>
<th>Details</th>
</tr>
<?php while ($res = mysqli_fetch_array($result)) { ?>
<tr>
<form action="update.php" method="post">
<td><input type="text" name="sku_p" value="<?php echo $res['sku_product']; ?>"></td>
<td><input type="text" name="name_p" value="<?php echo $res['name_product']; ?>"></td>
<td><input type="text" name="price_p" value="<?php echo $res['price_product']; ?>"></td>
<td><input type="text" name="type_p" value="<?php echo $res['type_product']; ?>"></td>
<td>
Size for DVD: <input type="text" name="sizedvd_p" value="<?php echo $res['sizedvd_product']; ?>"><br>
Weight for Book: <input type="text" name="weightbook_p" value="<?php echo $res['weightbook_product']; ?>"><br>
For Furniture<br>
H: <input type="text" name="heightfurn_p" value="<?php echo $res['heightfurn_product']; ?>"><br>
W: <input type="text" name="widthfurn_p" value="<?php echo $res['widthfurn_product']; ?>"><br>
L: <input type="text" name="lengthfurn_p" value="<?php echo $res['lengthfurn_product']; ?>"><br>
</td>
<input type="hidden" name="id_p" value="<?php echo $res['id_product']; ?>">
<input type="submit" name="update" value="Submit">
</form>
</tr>
<?php } ?>
<a href="index.php">Home</a>
</table>
</body>
</html>
和你的update.php
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "product_list";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
if (isset($_POST['update'])) {
$sql = "UPDATE products SET name_product = '$_POST[name_p]', price_product = '$_POST[price_p]', sku_product = '$_POST[sku_p]', type_product = '$_POST[type_p]', sizedvd_product = '$_POST[sizedvd_p]', weightbook_product = '$_POST[weightbook_p]', heightfurn_product = '$_POST[heightfurn_p]', widthfurn_product = '$_POST[widthfurn_p]', lengthfurn_product = '$_POST[lengthfurn_p]', WHERE id_product = '$_POST[id_p]'";
} else {
echo "Nothing was posted";
}
if (mysqli_query($conn, $sql)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($conn);
}
mysqli_close($conn);
?>
关于php + mysql 编辑\更新表单，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50595154/