mysql - 获取包含嵌套项目的记录node-mysql

Question

我在我的expressjs应用程序中使用node-mysql进行数据库查询操作，并且我想从查询中获取嵌套结果。但似乎我找不到一种简单的方法。

In their document I found Joins with overlapping column names which can query a table name and nested with a columns. However this is not suitable work around for one-to-many or many-to-many structure.

以下是表结构和预期结果的示例。

表格

tbl_order

id    customer_name    date
1     Perona           6/7/2018
2     Zorro            6/8/2018

tbl_order_items

id    order_id   item_name
1     2          compass
2     2          sword
3     2          yakuta
4     1          umbrella
5     1          doll

预期结果

我想获取所有订单和包含该订单的商品。

[
    {
       id: 1,
       customer_name: perona,
       data: 6/7/2018,
       items: [
          { id: 4, item_name: umbrella },
          { id: 5, item_name: doll },
       ]
    },
    {
       id: 2,
       customer_name: zorro,
       data: 6/8/2018,
       items: [
          { id: 1, item_name: compass },
          { id: 2, item_name: sword },
          { id: 3, item_name: yakuta },
       ]
    }
]

是否有任何选项可以在node-mysql中执行相同的操作？

Answer 1

您可以使用 INNER JOIN 根据关联获取嵌套数据。

SELECT [order].*,
       [items].[id] AS [items.id]
       [items].[item_name] AS [items.item_name]
FROM
(
    SELECT [id],
           [customer_name],
           [date]
    FROM [tbl_order]
) AS [order]
INNER JOIN
[tbl_order_items] AS [items]
ON
[order].[id] = [items].[order_id];