选择查询不工作。尽管我输入了正确的密码，但它直接进入登录失败。
我从另一个数据库尝试过，它可以工作，但从这个表来看，它不想工作。
另一件事是每当我启动 XAMPP 时它都会显示 key _ buffer。
这就是阻止我的查询工作的原因吗？
下面是我的代码。希望开发者能够提供一些帮助。
<?php
session_start();
$_SESSION['message']='';
$mysqli=new MySQLi('127.0.0.1','root','','learning_malaysia');
if(isset($_POST['login'])) {
$username = $mysqli->real_escape_string($_POST['username']);
$password = md5($_POST['password']);
$sql="SELECT * FROM tutor_register WHERE username='$username' AND password='$password' LIMIT 1;";
$result = mysqli_query($mysqli,$sql);
if(mysqli_num_rows($result) > 0){
$row = mysqli_fetch_array($result);
if (($row['username']=='sithi') && ($row['password']=='202cb962ac59075b964b07152d234b70')){
$_SESSION['user_type'] = $row;
$_SESSION['password'] = $row;
$_SESSION['message'] = "Registration successful!";
header("location:myresuming.html");
exit();
} else {
$_SESSION['username'] = $row['username'];
$_SESSION['profile'] = $row['profile'];
$_SESSION['message'] = "Registration successful!";
header("location:Welcome.php");
exit();
}
} else {
$_SESSION['message'] = "Login Failed!";
}
}
?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>form in Design</title>
<link rel="stylesheet" type="text/css" href="mystyle.css" />
<link rel="stylesheet" type="text/css" href="form.css" />
</head>
<body>
<div class="container"><?=$_SESSION['message']?>
<img src="5.jpg" />
<form class="form" action="" method="post" enctype="multipart/form-data" autocomplete="off">
<div class="alert alert-error"></div>
<input type="text" placeholder="User Name" name="username" required />
<input type="password" placeholder="Password" name="password" autocomplete="new-password" required />
<input type="submit" name="login" value="login" class="btn-login" />
</form>
</div>
</body>
</html>
最佳答案
<?php
session_start();
$_SESSION['message']='';
$mysqli=new MySQLi('127.0.0.1','root','','learning_malaysia');
if(isset($_POST['login'])) {
$username = $mysqli->real_escape_string($_POST['username']);
$password = md5($_POST['password']);
$sql="SELECT * FROM tutor_register WHERE username='$username' AND password='$password' LIMIT 1;";
$result = mysqli_query($mysqli,$sql);
if(mysqli_num_rows($result) > 0){
$row = mysqli_fetch_array($result);
if (($row['username']=='sithi') && ($row['password']=='202cb962ac59075b964b07152d234b70')){
$_SESSION['user_type'] = $row['user_type'];
$_SESSION['password'] = $row['password'];
$_SESSION['message'] = "Registration successful!";
header("location:myresuming.html");
exit();
} else {
$_SESSION['username'] = $row['username'];
$_SESSION['profile'] = $row['profile'];
$_SESSION['message'] = "Registration successful!";
header("location:Welcome.php");
exit();
}
} else {
$_SESSION['message'] = "Login Failed!";
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>form in Design</title>
<link rel="stylesheet" type="text/css" href="mystyle.css" />
<link rel="stylesheet" type="text/css" href="form.css" />
</head>
<body>
<div class="container"><?php echo $_SESSION['message']; ?>
<img src="5.jpg" />
<form class="form" action="" method="post" enctype="multipart/form-data" autocomplete="off">
<div class="alert alert-error"></div>
<input type="text" placeholder="User Name" name="username" required />
<input type="password" placeholder="Password" name="password" autocomplete="new-password" required />
<input type="submit" name="login" value="login" class="btn-login" />
</form>
</div>
</body>
</html>
试试这个。
关于php - 我的登录页面无法使用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50771810/