我有一个像这样的长字符串:
je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?
我想在 : 之后和之前拆分字符串? .所以我想把它放入数组中:
{e,es,e,ons,ez,en}
我知道我可以做到:
NSArray *subStrings = [stringToChange componentsSeparatedByString:@":"];
但这还不够。 请问我该怎么做?任何帮助将不胜感激!
最佳答案
另一种选择是使用 NSRegularExpression类。
使用这种模式:
\\:([^\?]+)\?
示例代码:
NSString *sample = @"je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?";
NSString *pattern = @"\\:([^\?]+)\?";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive
error:&error];
NSArray *matches = [regex matchesInString:sample
options:0
range:NSMakeRange(0, [sample length])];
if(!error && [matches count] > 0) {
for (NSTextCheckingResult *match in matches) {
NSRange matchRange = [match range];
NSLog(@"%@" ,[sample substringWithRange:matchRange]);
}
}
输出:
2015-07-03 12:16:39.037 TestRegex[3479:48301] :e
2015-07-03 12:16:39.039 TestRegex[3479:48301] :es
2015-07-03 12:16:39.039 TestRegex[3479:48301] :e
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ons
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ez
2015-07-03 12:16:39.040 TestRegex[3479:48301] :ent
关于ios - 在 : and before? 之后拆分字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31200088/