我正在尝试从数据库中求和(添加值)。我的应用程序检查每行的值,将每行的值加起来最多为 2000。一旦达到 2000,它就会保存在数据库中(插入查询)并继续相同的操作,直到获取最后一条记录。每行求和(或总计)的总值不应超过 2000。
有两个插入查询,一个用于插入总计(从 1800 到 2000 之间的每一行),并生成 ID(如主键),第二个表添加插入 ID 的每一行(生成的 ID 现在成为外键) )
请引用截图。
$i = 1;
do {
$id = $row_FetchRecordRS['ID'];
$dateissued = $row_FetchRecordRS['DateIssued'];
$rundateCarrierRun = $row_FetchRecordRS['RundateCarrierRunID'];
$timegenerated = $row_FetchRecordRS['TimeGenerated'];
$carrierID = $row_FetchRecordRS['CarrierRunID'] ;
$areaID = $row_FetchRecordRS['CarrierAreaID'];
$address = $row_FetchRecordRS['DeliveryAddress'];
$potzone = $row_FetchRecordRS['Postzone'];
$carr_ID = $row_FetchRecordRS['CarrierID'];
$instruction = $row_FetchRecordRS['DeliveryAddress'];
$areaRep = $row_FetchRecordRS['AreaRepDetails'];
// $vendor = $row_FetchRecordRS['VendorDetails'];
$quantity = $row_FetchRecordRS['Quantity'];
$direct = $row_FetchRecordRS['Direct'];
$jobID = $row_FetchRecordRS['JobID'];
$jobName = $row_FetchRecordRS['JobName'];
$bundlesize = $row_FetchRecordRS['Bundlesize'];
$bundle = $row_FetchRecordRS['Bundles'];
$items = $row_FetchRecordRS['Items'];
$weight = $row_FetchRecordRS['WeightKgs'];
$totalWeightCol = $row_FetchRecordRS['TotalWeightKgs'];
$date = date("D M d, Y G:i");
$total_weight = $row_FetchRecordRS['FinalWeight'] + $total_weight ;
echo "Row: " .$row_FetchRecordRS['FinalWeight']. "<br>";
echo "Total is______ $i : $total_weight <br><br>";
$sqlquerytest = "INSERT INTO `GenerateRun`
(`DateIssued`, `RundateCarrierRunID`, `TimeGenerated`,
`CarrierRunID`, `CarrierAreaID`, `DeliveryAddress`, `Postzone`,
`CarrierID`, `DeliveryInstruction`, `AreaRepDetails`,
`Quantity`, `Direct`, `JobID`, `JobName`, `Bundlesize`,
`Bundles`, `Items`, `WeightKgs`, `TotalWeightKgs`,
`LodingZoneID`)
VALUES
('$dateissued', '$rundateCarrierRun', '$timegenerated',
'$carrierID', '$areaID', '$address', '$potzone', '$carr_ID',
'$instruction', '$areaRep', '$quantity', '$direct', '$jobID',
'$jobName', '$bundlesize', '$bundle', '$items', '$weight',
'$totalWeightCol','$i')";
mysql_select_db($database_callmtlc_SalmatDB, $callmtlc_SalmatDB);
$ResultUpd1 = mysql_query($sqlquerytest, $callmtlc_SalmatDB) or die(mysql_error());
if ($total_weight >= 1800) {
$sqltransitlist = " INSERT INTO `TransitList`(`genID`, `total`) Values ('$i','$total_weight')";
mysql_select_db($database_callmtlc_SalmatDB, $callmtlc_SalmatDB);
$ResultUpd3 = mysql_query($sqltransitlist, $callmtlc_SalmatDB) or die(mysql_error());
$i = $i+1;
$total_weight = 0;
}
} while($row_FetchRecordRS = mysql_fetch_assoc($FetchRecordRS));
最佳答案
您的某些代码行与您的问题无关。我会为你简化它。
$i = 1;
$total = 0;
$arr = array(); // for storing a list of data provides that the total doesn't exceed 2000
while ($row = mysql_fetch_assoc($record)) {
$id = $row['id'];
$name = $row['name'];
$num = $row['num'];
$arr[] = array('id' => $id, 'name' => $name, 'num' => $num);
if ($num + $total > 2000) {
$sql = "INSERT INTO Table1(genID, total) Values ('$i','$total')";
mysql_query($sql) or die(mysql_error());
foreach ($arr as $data) {
$sql = "INSERT INTO Table2(ID, name, genID, total) Values ('$data[id]','$data[name]','$i','$data[num]')";
mysql_query($sql) or die(mysql_error());
}
$arr = array(); // empty the array as the data has been stored to database
$i++;
$total = 0;
} else { // if the total doesn't exceed 2000, add it to total
$total += $num;
}
}
$sql = "INSERT INTO Table1(genID, total) Values ('$i','$total')";
mysql_query($sql) or die(mysql_error());
foreach ($arr as $data) {
$sql = "INSERT INTO Table2(ID, name, genID, total) Values ('$data[id]','$data[name]','$i','$data[num]')";
mysql_query($sql) or die(mysql_error());
}
注意:此代码只是一个示例,而不是您的实际代码。您可以实现我的代码并将其与您的代码相匹配。
关于php - 如何获取记录求和到一个值然后添加到两个新表中?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51509995/