javascript - 如何从另一个表创建我的 php 表

Question

我的网站上有一个表格，代码如下 this is the table image

此表的代码

<?php
    $query = $db->query("SELECT * FROM bit_exchanges ORDER BY id DESC LIMIT 20"); 
    if($query->num_rows>0) {
        while($row = $query->fetch_assoc()) {
?>
            <tr>
                <td id="tabletext"><img src="<?php echo gatewayicon(gatewayinfo($row['gateway_send'],"name")); ?>" width="20px" height="20"> <?php echo gatewayinfo($row['gateway_send'],"name"); ?></td>
                <td id="tabletext"><img src="<?php echo gatewayicon(gatewayinfo($row['gateway_receive'],"name")); ?>" width="20px" height="20"> <?php echo gatewayinfo($row['gateway_receive'],"name"); ?></td>
                <td id="tabletext"><?php echo $row['amount_send']; ?> <?php echo gatewayinfo($row['gateway_send'],"currency"); ?></td>
                <td id="tabletext"><?php echo cropexchangeid($row['exchange_id'],8); ?></td>
                <td id="tabletext">
                <?php 
                    if($row['status'] == "1") {
                        echo '<span class="label label-warning"><i class="fa fa-clock-o"></i> '.$lang[status_1].'</span>';
                    } elseif($row['status'] == "2") {
                    	echo '<span class="label label-warning"><i class="fa fa-clock-o"></i> '.$lang[status_2].'</span>';
                    } elseif($row['status'] == "3") {
                    	echo '<span class="label label-info"><i class="fa fa-clock-o"></i> '.$lang[status_3].'</span>';
                    } elseif($row['status'] == "4") {
                    	echo '<span class="label label-success"><i class="fa fa-check"></i> '.$lang[status_4].'</span>';
                    } elseif($row['status'] == "5") {
                    	echo '<span class="label label-danger"><i class="fa fa-times"></i> '.$lang[status_5].'</span>';
                    } elseif($row['status'] == "6") {
                    	echo '<span class="label label-danger"><i class="fa fa-times"></i> '.$lang[status_6].'</span>';
                    } elseif($row['status'] == "7") {
                    	echo '<span class="label label-danger"><i class="fa fa-times"></i> '.$lang[status_7].'</span>';
                    } else {
                    	echo '<span class="label label-default">'.$lang[status_unknown].'</span>';
                    }
                ?>
                </td>
                <td id="tabletext"><?php echo date("d/m/Y",$row['created']) ?></td>
            </tr>
<?php
        }
    } else {
        echo '<tr><td colspan="5">'.$lang[still_no_exchanges].'</td></tr>';
    }
?>

我只想在当前表格底部创建一个新表格，其中包含仅“已处理”的所选行

我只想将这些行放入我的新表 see this image 当“正在处理”状态被处理时，它会自动进入新表。请帮助我创建此查询。

这是我的数据库图像，my database image我只想要整个表行为“4”请帮忙。

Answer 1

这可能听起来有点简单，但为什么不将第一个数据库查询更改为:

"SELECT * FROM bit_exchanges WHERE status <> 4 ORDER BY id DESC LIMIT X"

您将不会获得状态为4的行。 然后继续创建一个与您使用查询创建的表类似的新表

"SELECT * FROM bit_exchanges WHERE status=4 ORDER BY id DESC LIMIT X"

然后您可以删除 elseif 检查 ( elseif($row['status'] == "4" )。

您的第二个表-代码将如下所示:

<?php
    $query = $db->query("SELECT * FROM bit_exchanges WHERE status=4 ORDER BY id DESC LIMIT X"); 
    if($query->num_rows>0) {
        while($row = $query->fetch_assoc()) {
?>
            <tr>
                <td id="tabletext"><img src="<?php echo gatewayicon(gatewayinfo($row['gateway_send'],"name")); ?>" width="20px" height="20"> <?php echo gatewayinfo($row['gateway_send'],"name"); ?></td>
                <td id="tabletext"><img src="<?php echo gatewayicon(gatewayinfo($row['gateway_receive'],"name")); ?>" width="20px" height="20"> <?php echo gatewayinfo($row['gateway_receive'],"name"); ?></td>
                <td id="tabletext"><?php echo $row['amount_send']; ?> <?php echo gatewayinfo($row['gateway_send'],"currency"); ?></td>
                <td id="tabletext"><?php echo cropexchangeid($row['exchange_id'],8); ?></td>
                <td id="tabletext">
                <?php 
                        echo '<span class="label label-success"><i class="fa fa-check"></i> '.$lang[status_4].'</span>';
                ?>
                </td>
                <td id="tabletext"><?php echo date("d/m/Y",$row['created']) ?></td>
            </tr>