php - 如何使用php在下一页中显示与点击元素相关的信息

Question

$sql = "SELECT client_id, firm_name FROM savedata";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "<br> Client_id: ". $row["client_id"]. "<br> <a href ='view.php'>Client Name: ". $row["firm_name"]." </a>";
    }
} else {
    echo "0 results";
}

我使用此代码从数据库中显示我的客户名称，我想在 view.php 中显示与单击的客户相关的所有信息。

谢谢

Answer 1

更改此代码

echo "<br> Client_id: ". $row["client_id"]. "<br> <a href ='view.php'>Client Name: ". $row["firm_name"]." </a>";

至

echo "<br> Client_id: ". $row["client_id"]. "<br> <a href ='view.php?cid=".$row["client_id"]."'>Client Name: ". $row["firm_name"]." </a>";

然后在view.php中

$sql = "SELECT client_id, firm_name FROM savedata where client_id=".$_GET['cid'];
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    $row = $result->fetch_assoc();
    echo "<br> Client_id: ". $row["client_id"]. "<br> Client Name: ". $row["firm_name"];
 }