mysql - 将不同查询的输出合并为单个查询输出

Question

如何组合不同查询的输出。

我有以下 sql 查询及其输出:

1) select d.departmentid, d.name, count(distinct(sg.personid)) as noOfStudents from department d inner join course c on c.departmentid = d.departmentid inner join student_grade sg on sg.courseid = c.courseid group by d.departmentid, d.name;
+--------------+--------------+--------------+
| departmentid | name         | noofstudents |
+==============+==============+==============+
|          101 | Computer Sci |            1 |
|          104 | Mech         |            2 |
|          103 | EEE          |            1 |
+--------------+--------------+--------------+



2) select d.departmentid, d.name, count(distinct(ci.personid)) as noOfTeachers from department d inner join course c on c.departmentid = d.departmentid inner join course_instructor ci on ci.courseid = c.courseid group by d.departmentid, d.name;
+--------------+--------------+--------------+
| departmentid | name         | noofteachers |
+==============+==============+==============+
|          101 | Computer Sci |            1 |
|          103 | EEE          |            2 |
|          104 | Mech         |            1 |
|          102 | ECE          |            3 |
+--------------+--------------+--------------+

3) select d.departmentid, d.name, count(distinct(c.courseid)) as noOfCourses from department d inner join course c on c.departmentid = d.departmentid group by d.departmentid, d.name;
+--------------+--------------+-------------+
| departmentid | name         | noofcourses |
+==============+==============+=============+
|          101 | Computer Sci |           3 |
|          102 | ECE          |           3 |
|          104 | Mech         |           1 |
|          103 | EEE          |           2 |
+--------------+--------------+-------------+

现在我想将所有三个合并到一个表中来显示数据。 我怎样才能做到这一点？

这里我尝试UNION操作，好用吗？

Answer 1

如果您需要将学生、教师和类(class)作为输出中的单独列，您可以尝试如下操作:

select 
    d.departmentid, d.name, 
    count(distinct(sg.personid)) as noOfStudents, 
    0 as noofteachers, 0 as noofcourses 
from 
    department d 
inner join 
    course c on c.departmentid = d.departmentid 
inner join 
    student_grade sg on sg.courseid = c.courseid 
group by 
    d.departmentid, d.name

UNION ALL

select 
    d.departmentid, d.name, 0 as noOfStudents,
    count(distinct(ci.personid)) as noOfTeachers, 0 as noofcourses 
from 
    department d 
inner join 
    course c on c.departmentid = d.departmentid 
inner join 
    course_instructor ci on ci.courseid = c.courseid 
group by 
    d.departmentid, d.name

UNION ALL

select 
    d.departmentid, d.name, 0 as noOfStudents, 
    0 as noofteachers, count(distinct(c.courseid)) as noOfCourses 
from 
    department d 
inner join 
    course c on c.departmentid = d.departmentid 
group by 
    d.departmentid, d.name

这应该会产生这样的结果:

+--------------+--------------+--------------+--------------+--------------+  
| departmentid | name         | noofstudents | noofteachers | noofcourses  |  
+==============+==============+==============+==============+==============+  
|          101 | Computer Sci |             1|             0|             0|  
|          104 | Mech         |             2|             0|             0|  
|          103 | EEE          |             1|             0|             0|  
|          101 | Computer Sci |             0|             1|             0|  
|          103 | EEE          |             0|             2|             0|  
|          104 | Mech         |             0|             1|             0|  
|          102 | ECE          |             0|             3|             0|  
|          101 | Computer Sci |             0|             0|             3|  
|          102 | ECE          |             0|             0|             3|  
|          104 | Mech         |             0|             0|             1|  
|          103 | EEE          |             0|             0|             2|  
+--------------+--------------+--------------+--------------+--------------+  

如果您需要聚合值，只需将整个查询括在括号中并对结果求和即可

SELECT 
    departmentid, name, 
    SUM(noOfStudents), SUM(noOfTeachers), SUM(noOfCourses)
FROM 
    (Query1 UNION ALL Query2 UNION ALL Query3) AS mySubQuery
GROUP BY 
    departmentid, name