php - 如何: concatenate a php array generated from a mysql query?

Question

我正在使用 MYSQL/PHP 开发一个玩家姓名生成器。如何将一列(不包括主键)表的值选择为一维数组，然后将数组的值连接起来？

示例表“syllableInitials”:

characters
t
d
ch

php代码

$syllable = array("","","");

$sql = "SELECT characters FROM syllableInitials";
$result = $conn->query($sql);

$syllableInitials = array();

while ($initial = mysqli_fetch_row($result)) {
    $syllableInitials[] = $initial;
}
$syllableMedials = array("a", "o", "i");
$syllableFinals = array("m","s","d");

$syllable[0] = $syllableInitials[0] . $syllableMedials[2] . $syllableFinals[0];

echo "Syllable is: <b>" . $syllable[0] . "</b>";

我得到的输出是:

注意:数组到字符串的转换在线... 音节是:Arrayim

显然，上面示例代码的预期输出是“tim”而不是“Arrayim”。

syllableInitials 数组的 print_r 生成此...

Array (
     [0] => Array ( [0] => t )
     [1] => Array ( [0] => d ) 
    [2] => Array ( [0] => ch )
)

所以看起来我不知何故无意中嵌套了数组或导致它是二维的!我的编码真的很生疏...提前致谢!

Answer 1

由于 $initial 是一个数组并且只有一个元素，因此您可以执行以下操作:

$syllableInitials[] = $initial[0];

但更好的解决方案是使用 PDO 及其 PDOStatement::fetchColumn功能。

例如:

$syllable = array("","","");

$options = array(
    PDO::ATTR_PERSISTENT => true,
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);

$dbh = new PDO('mysql:dbname=dbname;host=127.0.0.1', 'username', 'password', $options);

$sth = $dbh->prepare('SELECT characters FROM syllableInitials');
$sth->execute();

$syllableInitials = array();

while ($initial = $sth->fetchColumn()) {
    $syllableInitials[] = $initial;
}
$syllableMedials = array("a", "o", "i");
$syllableFinals = array("m","s","d");

$syllable[0] = $syllableInitials[0] . $syllableMedials[2] . $syllableFinals[0];

echo "Syllable is: <b>" . $syllable[0] . "</b>";