我们有一个表,其中包含来自不同节点的数据,其中一列的状态报告为“合规或不合规”,示例数据如下
我想以这样的方式过滤表:如果节点上的任何检查显示不合规,则应将其标记为不合规,其余为合规。使用下面的查询我能够做到这一点
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
现在,我想按部门对结果进行分组和拆分,如下所示,如何实现此目的
最佳答案
我认为您正在寻找这个:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
关于mysql - 计算列中的不同值,同时按不同的列值进行总计和分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53577466/