因此，正如您在标题中所看到的，我正在寻找如何找到所有点赞的推文，然后将点赞的用户添加到此查询中，而不会丢失点赞的总结果。
这是我的喜欢表。
SELECT COUNT(*)
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id
GROUP BY likes.id_tweet;
+----------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+---------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | id_user | int(11) | NO | MUL | NULL | | | id_tweet | int(11) | NO | MUL | NULL | | +----------+---------+------+-----+---------+----------------+
When I run this query, I can get all the likes :
SELECT COUNT(*)
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id
GROUP BY likes.id_tweet;
像这样:
+----------+ | COUNT(*) | +----------+ | 1 | | 4 | | 1 | | 1 | | 2 | | 1 | | 1 | | 1 | | 1 | | 2 | | 1 | | 1 | | 3 | | 1 | | 1 | | 1 | | 1 | | 1 | | 1 | | 1 | | 3 | | 2 | | 1 | | 1 | | 2 | | 1 | | 3 | | 1 | | 1 | | 1 | | 3 | | 3 | | 2 | +----------+
我得到了所有的喜欢，但是当我添加
where likes.id_users = ...我只为一个用户点赞而失去了所有点赞，具体来说，我想恢复用户点赞的所有推文的点赞。
像这样
+-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+ | all likes | id | id_reply | id_poster | id_retweet | text | id_img | tweet_date | +-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+ | 50 | 2 | NULL | 1714 | NULL | Mon premier tweet | NULL | 2019-01-23 14:25:24 | | 43 | 35 | NULL | 1752 | NULL | Phasellus id sapien in sapien iaculis congue. Vivamus metus arcu, adipiscing molestie, hendrerit at, vulputate vitae, nisl. Aenean lectus. P | NULL | 2018-04-29 00:00:00 | | 22 | 50 | NULL | 1908 | NULL | In congue. Etiam justo. Etiam pretium iaculis justo. In hac habitasse platea dictumst. Etiam faucibus cursus urna. Ut tellus. | NULL | 2018-05-23 00:00:00 | +-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+
谢谢
最佳答案
试试这个:
SELECT COUNT(*), GROUP_CONCAT(likes.[id_user])
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id
GROUP BY likes.id_tweet;
关于php - 选择用户喜欢的推文中的所有喜欢，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54360729/