MYSQL-显示受聘年限

Question

问题是:

Display the number of years the employee is hired as NUM_OF_YEARS and sort the list by lastname.

这是在另一台电脑上使用的代码，运行良好。

SELECT  `lastname` AS "LASTNAME", 
DATE_FORMAT(`hire_date`,'%d-%M-%Y') AS "HIRED DATE",
TRUNCATE(DATEDIFF(CURDATE(),CONVERT(`hire_date`,DATETIME))  / 365 ,0) AS "NO_OF_YEARS",
DATEDIFF(YEAR(), `hire_date`, CURDATE()) AS "DATE"
FROM `activity6`.`employee`;

现在，当我尝试使用 Xampp (3.2.2) 并使用上面相同的代码运行它时，这是我得到的错误:

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '), hire_date, CURDATE()) AS "DATE" FROM activity6.employee' at line 5

这是我创建的表，上面的代码必须使用该表。----

因此，同时我需要创建另一列来显示这些员工截至该日期(2019 年)的年数。 我真的不确定什么是正确的查询。

Answer 1

在DATEDIFF函数中，您使用了3个参数，而该函数需要2个参数，我删除了YEAR()参数:

SELECT  `lastname` AS "LASTNAME", 
        DATE_FORMAT(`hire_date`,'%d-%M-%Y') AS "HIRED DATE",
        TRUNCATE(DATEDIFF(CURDATE(),CONVERT(`hire_date`,DATETIME))  / 365 ,0) AS "NO_OF_YEARS",
        DATEDIFF( `hire_date`, CURDATE()) AS "DATE"
FROM `activity6`.`employee`;