我有一个简单的mysql表,我想总结一下。这是我的 table
表名称:hauling_trip
列:
ID, CONTRACTOR, HAULING_SHEET_NO, FROM_LOCATION, TO_LOCATION, LOAD_WEIGHT_KG, PASS_NO
数据:
1 PM A00001 Stumping A Pangkalan 940.00 112233
2 PM A00002 Stumping B Pangkalan 530.00 112233
3 PM A00003 Stumping B Pangkalan 970.00 112244
4 PM A00004 Stumping A Pangkalan 450.00 112244
5 TKF A00005 Stumping A Pangkalan 850.00 112255
6 TKF A00006 Stumping B Pangkalan 780.00 112255
7 TKF A00007 Stumping A Pangkalan 903.00 112266
我想要做的是,我想通过显示每个 PASS_NO 的总行程次数和负载重量(KG)来总结此表。这是想要的结果
PASS_NO CONTRACTOR WEIGHT_A TRIP_A WEIGHT_B TRIP_B
112233 PM 940.00 1 530.00 0
112244 PM 450.00 0 970.00 1
112255 TKF 850.00 1 780.00 0
112266 TKF 903.00 1 0.00 0
相同的PASS_NO表示,拖运单被假定为1趟。例如,拖运单 A00001 和 A00002 具有相同的 PASS_NO,即 112233。因此,两个拖运单都属于 1 个行程,并且该行程属于 FROM_LOCATION 绊倒 A,因为重量大于绊倒 B。
这是我目前正在处理的查询。但我不知道如何才能顺利完成行程。
SELECT
a.PASS_NO,
a.CONTRACTOR,
( SELECT sum( LOAD_WEIGHT_KG ) FROM hauling_trip WHERE PASS_NO = a.PASS_NO AND FROM_LOCATION = 'Stumping A' ) AS WEIGTH_A,
( SELECT count( PASS_NO ) FROM hauling_trip WHERE PASS_NO = a.PASS_NO AND FROM_LOCATION = 'Stumping A' ) AS TRIP_A,
( SELECT sum( LOAD_WEIGHT_KG ) FROM hauling_trip WHERE PASS_NO = a.PASS_NO AND FROM_LOCATION = 'Stumping B' ) AS WEIGHT_B,
( SELECT count( PASS_NO ) FROM hauling_trip WHERE PASS_NO = a.PASS_NO AND FROM_LOCATION = 'Stumping B' ) AS TRIP_B,
SUM(a.LOAD_WEIGHT_KG) AS TOTAL_WEIGHT
FROM
hauling_trip AS a
GROUP BY
a.PASS_NO, a.CONTRACTOR
最佳答案
使用条件聚合:
SELECT ht.PASS_NO, ht.CONTRACTOR,
sum(case when ht.from_location = 'Stumping A' then ht.load_weight_kg end) as weight_a,
sum(ht.from_location = 'Stumping A') as trip_a,
sum(case when ht.from_location = 'Stumping B' then ht.load_weight_kg end) as weight_b,
sum(ht.from_location = 'Stumping B') as trip_b
sum(ht.LOAD_WEIGHT_KG) AS TOTAL_WEIGHT
FROM hauling_trip ht
GROUP BY ht.PASS_NO, ht.CONTRACTOR
关于mysql - 使用子查询汇总Mysql表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54394519/