php - MySQL自连接获取有序父子记录

Question

我有一个具有以下结构的表:

+-----------+--------------+-----------+----------+
| member_id | household_id | firstName | lastName |
+-----------+--------------+-----------+----------+
| 14122     | 0            | Cynthia   | Bookout  |
+-----------+--------------+-----------+----------+
| 14123     | 0            | Kim       | Caves    |
+-----------+--------------+-----------+----------+
| 14124     | 14122        | Marvin    | Bookout  |
+-----------+--------------+-----------+----------+
| 14125     | 13974        | Stacey    | Webb     |
+-----------+--------------+-----------+----------+
| 14126     | 13974        | Nathan    | Webb     |
+-----------+--------------+-----------+----------+
| 14127     | 13974        | Adam      | Webb     |
+-----------+--------------+-----------+----------+
| 14128     | 13974        | Thomas    | Webb     |
+-----------+--------------+-----------+----------+
| 14129     | 0            | Missy     | Hammock  |
+-----------+--------------+-----------+----------+
| 14130     | 0            | Stephanie | Lewis    |
+-----------+--------------+-----------+----------+
| 14131     | 0            | Kelly     | Hutto    |
+-----------+--------------+-----------+----------+
| 14132     | 14130        | James     | Lewis    |
+-----------+--------------+-----------+----------+
| 14133     | 0            | Cindy     | Barnwell |
+-----------+--------------+-----------+----------+
| 14134     | 13828        | NATALIE   | MCMILLAN |
+-----------+--------------+-----------+----------+
| 14135     | 13828        | Steven    | Adams    |
+-----------+--------------+-----------+----------+
| 14136     | 0            | Katherine | Gaskins  |
+-----------+--------------+-----------+----------+

对于某些记录，

member_id 和 household_id 具有父子关系。例如，member_id 14124 的记录是 member_id 14122 的子记录(即，其 household_id 是它的父级)。

该表实际上包含数千条不按顺序排列的记录。我想显示它们，以便父记录后面跟着其子记录，然后出现下一个父记录及其子记录，依此类推。结果也需要按 member_id 排序。

我已经尝试过这个:

SELECT * FROM members WHERE household_id IN (SELECT member_id FROM members WHERE household_id = 0) OR household_id = 0
ORDER BY member_id

但我没有得到想要的结果。使用 PHP 以编程方式执行此操作花费的时间太长，因为我必须多次迭代每条记录。

这是我想要的结果:

+-----------+--------------+--------------+----------+
| member_id | household_id | firstName    | lastName |
+-----------+--------------+--------------+----------+
| 14122     | 0            | Cynthia      | Bookout  |
+-----------+--------------+--------------+----------+
| 14124     | 14122        | Marvin Keith | Bookout  |
+-----------+--------------+--------------+----------+
| 14123     | 0            | Kim          | Caves    |
+-----------+--------------+--------------+----------+
| 14125     | 13974        | Stacey       | Webb     |
+-----------+--------------+--------------+----------+
| 14126     | 13974        | Nathan       | Webb     |
+-----------+--------------+--------------+----------+
| 14127     | 13974        | Adam         | Webb     |
+-----------+--------------+--------------+----------+
| 14128     | 13974        | Thomas       | Webb     |
+-----------+--------------+--------------+----------+
| 14129     | 0            | Missy        | Hammock  |
+-----------+--------------+--------------+----------+
| 14130     | 0            | Stephanie    | Lewis    |
+-----------+--------------+--------------+----------+
| 14132     | 14130        | James        | Lewis    |
+-----------+--------------+--------------+----------+
| 14131     | 0            | Kelly        | Hutto    |
+-----------+--------------+--------------+----------+
| 14133     | 0            | Cindy        | Barnwell |
+-----------+--------------+--------------+----------+
| 14134     | 13828        | NATALIE      | MCMILLAN |
+-----------+--------------+--------------+----------+
| 14135     | 13828        | Steven       | Adams    |
+-----------+--------------+--------------+----------+
| 14136     | 0            | Katherine    | Gaskins  |
+-----------+--------------+--------------+----------+

Answer 1

尝试以下查询:

SELECT a.member_id as parent_id,
       a.firstName as parent_firstName,
       a.lastName as parent_lastName,
       b.member_id as child_id,
       b.firstName as child_firstName,
       b.lastName as child_lastName
FROM members a inner join members b on a.member_id = b.household_id
ORDER BY a.member_id

query_output