我有一个简单的查询
select *, FIRST(m.id), MAX(mj.meeting_day) from Member m
left join SaveWork as s on s.member_id = m.id
left join Points as mp on mp.id = s.point_id
left join Aggr as mj on mj.id = mp.aggr_id
where m.congregation_id = 2
GROUP BY m.id
但是当我尝试执行它时,我得到
#1064 - Something is wrong in your syntax near '(m.id) from Member m
left join SaveWork as s on s.member_id = m.id
left join M' in line 1
我不知道为什么会发生这种情况,我认为这与此有关 Expression #24 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'sprawy.s.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
,我想当我使用 FIRST
时函数它将解决我的问题,但这并没有发生,欢迎任何帮助
最佳答案
你可以尝试下面 - first() 函数在 mysql 中不可用,你可以使用 limit 代替
select m.id, MAX(mj.meeting_day) from Member m
left join SaveWork as s on s.member_id = m.id
left join Points as mp on mp.id = s.point_id
left join Aggr as mj on mj.id = mp.aggr_id
where m.congregation_id = 2
GROUP BY m.id order by m.id
limit 1
关于MySQL,不能在简单查询中使用group by,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54474912/