我正在尝试计算所有状态为已 checkout 的行, 但我只能做的是按行填充它然后动态计数。
如何将我的行作为标题,然后计算之后的状态?
我需要将宿舍名称行作为列标题 然后按行 checkout 。
查询:
SELECT Room_Number as 'Room Number',Dorm_Name as 'Dorm Name',
COUNT(IF(action = 'Checked Out' , 1, NULL)) 'Checked Out' FROM billeting_history group by dorm_name;
+-----------+-------------+-------------+
| Dorm Name | Room_number | Checked Out |
+-----------+-------------+-------------+
| Arquitola | 205 | 1 |
| Hangar | 201 | 0 |
| Noble | 200 | 0 |
+-----------+-------------+-------------+
Desired output :
+-------------+-----------+--------+-------+
| Room Number | Arquitola | Hangar | Noble |
+-------------+-----------+--------+-------+
| 205 | 1 | 0 | 0 |
| 201 | 0 | 0 | 0 |
| 200 | 0 | 0 | 0 |
+-------------+-----------+--------+-------+
最佳答案
如果您知道所需的特定列,则可以使用条件聚合:
SELECT Room_Number,
SUM( CASE WHEN Dorm_Name = 'Arquitola' THEN checked_out ELSE 0 END ) as Arquitola,
SUM( CASE WHEN Dorm_Name = 'Hangar' THEN checked_out ELSE 0 END ) as Hangar,
SUM( CASE WHEN Dorm_Name = 'Noble' THEN checked_out ELSE 0 END ) as Noble
FROM billeting_history
GROUP BY Room_Number;
如果您不知道完整的名称列表,那么您需要使用动态 SQL。
关于mysql - 如何将行作为标题然后计算填充的数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54649752/