javascript - PHP、HTML JS MySQL 动态下拉菜单

Question

我有一个表单，除了...用户应选择部门，并且 4 个缺陷字段应填充与部门匹配的缺陷之外，所有内容均已正常工作并提交。部门和缺陷4工程。如果我删除 4 则 3 个作品，删除 4&3 和 2 个作品，依此类推。我认为它正在丢失列表索引，但我迷路了。我已将各个变量更改为每个缺陷中唯一的，并且结果相同。我只是脑子卡住了，语法上我遗漏了一些东西。以下是部门、缺陷 1 和 2 的代码。

    <strong>Department Name:</strong>
        <select name=Department_Nam class="required-entry" id="Department_Nam" onchange="javascript: dynamicdropdown(this.options[this.selectedIndex].value);">
            <option value="">Select Department</option>
            <?php if ($resultdep->num_rows > 0) {
              while($row = mysqli_fetch_assoc($resultdep)) {?>
                <option value="<?php echo $row['Department_Nam']; ?>"> <?php echo $row['Department_Nam']; ?></option>

          <?php        }
             } ?>

        </select>
    </div>

    <strong>Defect:</strong><br>
        <script>
            document.write('<select name="DefectDescrip" id="DefectDescrip"> <option value="">Please select defect</option></select>')
        </script>
        <noscript>
            <select name="DefectDescrip" id="DefectDescrip">
                <option value="">Please select defect</option>
            </select>
        </noscript>
    </div>
    <script>
        var rowFrameworkResultInJs =<?php echo json_encode($rowFrameworkResult);?>;
        function dynamicdropdown(listindex)
        {
            document.getElementById("DefectDescrip").length = 0;
            document.getElementById("DefectDescrip").options[0]=new Option("Please select defect","");
            if (listindex) {
                var lookup = {};
                var j = 1;
                for (var i = 0, len = rowFrameworkResultInJs.length; i < len; i++) {
                    if (rowFrameworkResultInJs[i].Reject_Code_Department == listindex) {
                        document.getElementById("DefectDescrip").options[j]=new Option(rowFrameworkResultInJs[i].Reject_Code_Descrip,rowFrameworkResultInJs[i].Reject_Code_Descrip);
                        j = j+1;
                    }
                }
            }
         return true;   
        }
   </script>


   <br><strong>Defect 2:</strong><br>
        <script>
            document.write('<select name="DefectDescrip2" id="DefectDescrip2"><option value="">Please select defect</option></select>')
        </script>
        <noscript>
            <select name="DefectDescrip2" id="DefectDescrip2">
                <option value="">Please select defect</option>
            </select>
        </noscript>
    </div>
    <script>
        var rowFrameworkResultInJs =<?php echo json_encode($rowFrameworkResult);?>;
        function dynamicdropdown(listindex)
        {
            document.getElementById("DefectDescrip2").length = 0;
            document.getElementById("DefectDescrip2").options[0]=new Option("Please select defect","");
            if (listindex) {
                var lookup = {};
                var j = 1;
                for (var i = 0, len = rowFrameworkResultInJs.length; i < len; i++) {
                    if (rowFrameworkResultInJs[i].Reject_Code_Department == listindex) {
                        document.getElementById("DefectDescrip2").options[j]=new Option(rowFrameworkResultInJs[i].Reject_Code_Descrip,rowFrameworkResultInJs[i].Reject_Code_Descrip);
                        j = j+1;
                    }
                }
            }

            return true;
        }
   </script>

Answer 1

已修复。我正在调用部门中的一个函数，需要添加单独的函数调用并更改被调用的函数以匹配。哇，头抽筋了。