因此，当我尝试仅修改数据库中的 1 个用户列数据时遇到问题。我编写的代码只会修改数据库中最后一个用户的数据，而不是当前用户的数据。
例如:我使用以下列登录 Asd 帐户:
电子邮件用户名 number prenume tara
如果我编辑它，它将在数据库中显示该值，但不会在屏幕上显示它们
如果我有更多像 asd abc abcd 这样的用户
它将显示 abcd 的值
<?php include('server.php');
$result = mysqli_query($db,"SELECT * FROM users");
while($row = mysqli_fetch_array($result))
{
if($username=$row['username'])
{
$email=$row['email'];
$user=$row['username'];
$nume=$row['nume'];
$prenume=$row['prenume'];
$tara=$row['tara'];
$oras=$row['oras'];
$adresa=$row['adresa'];
$numar=$row['numar'];
}
}
?>
<form method="post" action="editprofil.php">
<table class="table-fill">
<thead>
<tr>
<th class="text-left" style="font-size:32px;padding-bottom:1em;" >Profil</th>
</tr>
</thead>
<tbody>
<tr>
<td class="text-left">Username</td>
<td class="text-left"><?php echo $user ?></td>
</tr>
<tr>
<td class="text-left">Nume</td>
<td class="text-left"><input type="text" name="nume" /></td>
</tr>
<tr>
<td class="text-left">Prenume</td>
<td class="text-left"><input type="text" name="prenume" /></td>
</tr>
<tr>
<td class="text-left" >Email </td>
<td class="text-left"> <?php echo $email; ?></td>
</tr>
<tr>
<td class="text-left">Tara</td>
<td class="text-left"><input type="text" name="tara" /></td>
</tr>
<tr>
<td class="text-left">Oras</td>
<td class="text-left"><input type="text" name="oras" /></td>
</tr>
<tr>
<td class="text-left">Adresa</td>
<td class="text-left"><input type="text" name="adresa"/></td>
</tr>
<tr>
<td class="text-left">Telefon mobil</td>
<td class="text-left"><input type="text" name="telefon" /></td>
</tr>
<tr>
<td class="text-left">Data nasterii</td>
<td class="text-left"><input type="text" name="varsta" /></td>
</tr>
</tbody>
</table>
<div class="input-container"style="padding-top:1em;">
<input type="username" name="username" id="#{label}" />
<label for="#{label}">Confirm username</label>
<div class="bar"></div>
</div>
<div class="input-container"style="padding-top:1em;">
<input type="password" name="password" id="#{label}" />
<label for="#{label}">Confirm password</label>
<div class="bar"></div>
</div>
<div class="button-container">
<button type="submit" class="btn" name="edit_user">Register</button>
</div>
</form>
服务器.php
<?php
session_start();
$username = "";
$oras ="";
$nume ="";
$prenume ="";
$tara ="";
$adresa ="";
$telefon ="";
$varsta ="";
$email="";
$errors = array();
$db = mysqli_connect('localhost', 'root', '12345678', 'registration');
if (isset($_POST['reg_user'])) {
$username = mysqli_real_escape_string($db, $_POST['username']);
$email = mysqli_real_escape_string($db, $_POST['email']);
$password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
$password_2 = mysqli_real_escape_string($db, $_POST['password_2']);
if (empty($username)) { array_push($errors, "Username is required"); }
if (empty($email)) { array_push($errors, "email is required"); }
if (empty($password_1)) { array_push($errors, "Password is required"); }
if ($password_1 != $password_2) {
array_push($errors, "The two passwords do not match");
}
$user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
$result = mysqli_query($db, $user_check_query);
$user = mysqli_fetch_assoc($result);
if ($user) { // if user exists
if ($user['username'] === $username) {
array_push($errors, "Username already exists");
}
if ($user['email'] === $email) {
array_push($errors, "email already exists");
}
}
if (count($errors) == 0) {
$password = md5($password_1);//encrypt the password before saving in the database
$query = "INSERT INTO users (username, email, password)
VALUES('$username', '$email', '$password')";
mysqli_query($db, $query);
$_SESSION['username'] = $username;
$_SESSION['email'] = $email;
$_SESSION['success'] = "You are now logged in";
header('location: primapagina.php');
}
}
if (isset($_POST['login_user'])) {
$username = mysqli_real_escape_string($db, $_POST['username']);
$password = mysqli_real_escape_string($db, $_POST['password']);
if (empty($username)) {
array_push($errors, "Username is required");
}
if (empty($password)) {
array_push($errors, "Password is required");
}
if (count($errors) == 0) {
$password = md5($password);
$query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
$results = mysqli_query($db, $query);
if (mysqli_num_rows($results) == 1) {
$_SESSION['username'] = $username;
$_SESSION['email'] = $email;
$_SESSION['success'] = "You are now logged in";
header('location: primapagina.php');
}else {
array_push($errors, "Wrong username/password combination");
}
}
}
if (isset($_POST['edit_user']))
{
$oras = mysqli_real_escape_string($db, $_POST['oras']);
$tara = mysqli_real_escape_string($db, $_POST['tara']);
$adresa = mysqli_real_escape_string($db, $_POST['adresa']);
$nume = mysqli_real_escape_string($db, $_POST['nume']);
$prenume = mysqli_real_escape_string($db, $_POST['prenume']);
$telefon = mysqli_real_escape_string($db, $_POST['telefon']);
$varsta = mysqli_real_escape_string($db, $_POST['varsta']);
$password = md5(mysqli_real_escape_string($db, $_POST['password']));
$username = mysqli_real_escape_string($db, $_POST['username']);
$sql = "UPDATE users SET tara='$tara', oras='$oras', nume='$nume', prenume='$prenume', tara='$tara', adresa='$adresa' WHERE password = '$password' and username='$username' ";
mysqli_query($db, $sql);
}
?>
最佳答案
正如 @ AKX 所写，当您输入“$username = $row['username']”时，您将该行的用户名分配给 $username 并始终为 true，执行其中的代码如果所有时间都是您的所有记录。在这里您可以找到更多信息PHP If PHP Expressions
关于php - 显示变量从 1 .php 到另一个 .php 时出现问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54763697/