mysql - 在nodejs中使用关联和排序来 Sequelize findAll

Question

我正在尝试通过以下方式让所有用户及其主供应商、预订和服务在 booking_date 之前订购。

Users.findAll({
            where: { id: userId }, attributes: AttributesUser,
            include: [{
                model: MasterVendor, attributes: AttributesMasterVendor, required: true,
                include: [{
                    model: Bookings, where: { booking_state: jobStatus, booking_date: _date }, attributes: AttributesBooking,
                    include: [{ model: Services, attributes: attributesService, order: ['Bookings.booking_date'] }],
                }],
            }],
        });

但不幸的是，order by 子句根本没有生成。但是当我尝试按名称获取数据顺序时，它工作得很好

Users.findAll({
            where: { id: userId }, attributes: AttributesUser,
            include: [{
                model: MasterVendor, attributes: AttributesMasterVendor, required: true,
                include: [{
                    model: Bookings, where: { booking_state: jobStatus, booking_date: _date }, attributes: AttributesBooking,
                    include: { model: Services, attributes: attributesService }
                }]
            }],
            order: ['name'],
        });

请建议我，我做错了什么。 谢谢。

Answer 1

试试这个

在订单数组中包含型号名称。

Users.findAll({
            where: { id: userId }, attributes: AttributesUser,
            include: [{
                model: MasterVendor, attributes: AttributesMasterVendor, required: true,
                include: [{
                    model: Bookings, where: { booking_state: jobStatus, booking_date: _date }, attributes: AttributesBooking,
                    include: { model: Services, attributes: attributesService }
                }]
            }],
            order: [[Bookings, 'booking_date', 'DESC']],
        });