java - 当嵌套方法中发生错误时，不会发生事务回滚

Question

在我最近的项目中，我遇到了一个场景，当嵌套方法发生错误时，我需要回滚数据库操作。早些时候，我在单一方法上使用了@Transactional。那一次效果很好。但在当前情况下，我依赖于另一种方法。所以我需要在嵌套方法发生错误时回滚。我想用这个方法回滚

@Transactional
@Override
public String updateCustomOfficeHour(OfficeHour officeHour) {
    if (officeHour.getId() == null || officeHourRepository.getFirstById(officeHour.getId()) == null)
        throw new EntityNotFoundException("No Office-Hour found with this id");

    OfficeHour temp = officeHourRepository.getFirstById(officeHour.getId());
    List<OfficeHour> officeHours = officeHourRepository.findByFromDateAndToDate(temp.getFromDate(), temp.getToDate());

    List<OfficeHour> tempList = new ArrayList<>();
    for (OfficeHour officeHourObj : officeHours) {
        officeHourObj.setDeleted(true);
        tempList.add(officeHourObj);
    }
    officeHourRepository.saveAll(tempList);
    this.createCustomOfficeHour(officeHour);
    return "Updated Custom-Office-Hour";
}

这里我有一个数据库操作 officeHourRepository.saveAll(tempList); 当方法 this.createCustomOfficeHour(officeHour); 发生错误时，我需要回滚。这个方法是

   @Transactional
    @Override
    public String createCustomOfficeHour(OfficeHour officeHour) {
        if (officeHour.getFromDate() == null || officeHour.getToDate() == null
                || officeHour.getFirstOutTime() == null || officeHour.getLastInTime() == null
                || officeHour.getInTime() == null || officeHour.getOutTime() == null)
            throw new EntityNotFoundException("Null value received for OfficeHour fields!");

        if (officeHour.getToDate().compareTo(officeHour.getFromDate()) < 0)
            throw new EntityNotFoundException("FromDate is Getter than ToDate");

        if (officeHourRepository.isFromDateExist(officeHour.getFromDate()).longValue() > 0
                || officeHourRepository.isToDateExist(officeHour.getToDate()).longValue() > 0) {
            throw new EntityNotFoundException("FromDate/ToDate is already assigned");
        }

        if (officeHourRepository.isDateExistsBetweenFromAndToDate(officeHour.getFromDate(), officeHour.getToDate()).longValue() > 0)
            throw new EntityNotFoundException("Office Hour Already Assigned In This Range");


        for (int i = 1; i <= count; i++) {
           ........
           ........
           ........
           officeHourRepository.save(obj);

        }
        return "Custom Office-Hour Created";
    }

这是我的Exception类

public class EntityNotFoundException extends RuntimeException {

    public EntityNotFoundException(String message) {
        super(message);
    }
}

我还在application.properties中添加了spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQL5InnoDBDialect

任何帮助将不胜感激。

Answer 1

您的 EntityNotFoundException 是一个未经检查的异常，并且遵循 spring docs :

Spring default behavior for declarative transaction management follows EJB convention (roll back is automatic only on unchecked exceptions)

默认情况下事务应该回滚。

这是因为 updateCustomOfficeHour 和 createCustomOfficeHour 在同一事务下处理(此处没有覆盖传播，因此使用默认的 REQUIRED)。

您可以在 updateCustomOfficeHour 方法上为异常添加显式回滚，但这应该是多余的:

@Transactional(rollbackFor = {EntityNotFoundException.class})