我是一个刚刚学习的新人。我的 mySQL 数据库中有 3 个表,第一个“用户”,第二个产品_详细信息和第三个产品_图像。他们使用外键加入。喜欢 :
mySql Tables ,我正在使用 php PDO oops 来实现所需的输出。
我想显示带有产品图像的特定用户产品的列表。
所以我得到的对象如下:
[
{
"user_id": "1",
"product_id": "7",
"product_name": "product title",
"product_description": "product description",
"product_img_id": "1",
"product_img_path": "/products/product1.jpg",
"product_img_type": "main"
},
{ ... },
{ ... },
{ ... },
]
我的 Php 对象类功能代码:
function read(){
$query = "SELECT
p.user_id, p.product_id, p.product_name, p.product_description,
p1.product_img_id, p1.product_img_path, p1.product_img_type
FROM user AS p
LEFT JOIN product_description AS p1
ON p.product_id = p1.product_id
ORDER BY p.user_id DESC, p.product_id DESC";
$stmt = $this->conn->prepare($query);
$stmt->execute();
return $stmt;
}
这是我的创建对象代码:
if ($num > 0) {
$products_arr = array();
while ($row = $stmt -> fetch(PDO:: FETCH_ASSOC)) {
extract($row);
$product_item = array(
"user_id" => $user_id,
"product_id" => $product_id,
"product_name" => $product_name,
"product_description" => $product_description,
"product_img_id" => $product_img_id,
"product_img_path" => $product_img_path,
"product_img_type" => $product_img_type
);
$products_arr[] = $product_item;
}
echo json_encode($products_arr);
}
所以我需要一个像这样的对象:
{
"user_id" : "1",
"product" : [
{
"user_id": "1",
"product_id": "1",
"product_name": "product title ",
"product_description": "this is product description",
"product_images": [
{
"product_img_id": "1",
"product_img_path": "/products/product1.jpg",
"product_img_type": "main"
},
{...},
{...},
{...},
{...}
]
},
{...},
{...},
{...}
]
}
我想要
{ **user**
{ all **product** of this user {
all **images** of this product
}
}
}
最佳答案
在您的 php 代码中,您可以将以下代码更改为底部的代码
$product_item = array(
"user_id" => $user_id,
"product_id" => $product_id,
"product_name" => $product_name,
"product_description" => $product_description,
"product_img_id" => $product_img_id,
"product_img_path" => $product_img_path,
"product_img_type" => $product_img_type
);
以下内容:
$product_image = array(
"product_img_id" => $product_img_id,
"product_img_path" => $product_img_path,
"product_img_type" => $product_img_type
);
$product = [
"product_id" => $product_id,
"product_name" => $product_name,
"product_description" => $product_description,
"product_images" => $product_image
];
$product_item = array(
"user_id" => $user_id,
"product" => $product
);
关于php - 从 PHP INNER JOIN 表创建多维 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55699300/