我正在制作一个应用程序,用户可以在其中与其他用户聊天(一对一,而不是群聊)。我有一个 MySQL 表,用于存储来自每个用户的所有消息,例如:
from_id to_id message time
abc123 def456 Hello 789
def456 abc123 What's up? 1234`
def456 abc123 How was last night? 2345
abc123 p0tat0 I missed the bus 3456
def456 p0tat0 I hate you :( 4567`
def456 another_user I hate Potato! 5678`
如何获取从 AND 到 abc123
的最新消息(从最新到最旧排序),例如:
from_id to_id message time
abc123 p0tat0 I missed the bus 3456
def456 abc123 How was last night? 2345
如果重要的话,time
在消息表中将始终按升序排列。
任何帮助将不胜感激。谢谢^.^
SELECT *,
'from' as direction
FROM messages WHERE from_username='admin' AND 'time' = ( SELECT MAX('time') FROM messages WHERE from_username='admin'
OR to_username='admin'
)
UNION ALL
SELECT *,
'to' as direction
FROM messages WHERE to_username='admin' AND 'time' = ( SELECT MAX('time') FROM messages WHERE
to_username='admin' OR
to_username='admin' )
最佳答案
试试这个
SELECT * FROM
messageTable
WHERE from_id='abc123'
AND `time` = ( SELECT MAX(`time`) FROM messageTable WHERE from_id='abc123' )
UNION ALL
SELECT * FROM
messageTable
WHERE to_id='abc123'
AND `time` = ( SELECT MAX(`time`) FROM messageTable WHERE to_id='abc123' )
关于MySQL获取最新的对话消息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57488906/