mysql - Laravel 中的嵌套查询

Question

这是我的 sql，我正在努力将其转换为 laravel 5.8 查询生成器语法。

    SELECT CC AS CountOfVisits, Count(CC) AS Users
    FROM
        (
        SELECT user_id, count(user_id) AS CC FROM mytable
        GROUP BY user_id
        ) AS CC
    GROUP BY CC;

我尝试过这个:

     $frequency= DB::connection('mysql2')
            ->select(DB::raw('CC AS CountOfVisits'), DB::raw('Count(CC) AS Users'))
            ->from(function($sq)
            {
               $sq->select(DB::raw('user_id, count(user_id) AS CC FROM '))
                    ->from('mytable')
                    ->groupBy('user_id');
            })
            ->groupBy('CC')
            ->get();

它的错误

Argument 1 passed to Illuminate\Database\Connection::prepareBindings() must be of the type array, object given, called in /var/app/portal/vendor/laravel/framework/src/Illuminate/Database/Connection.php on line 665

任何帮助都会非常感谢

Answer 1

我认为您遇到的问题是返回的连接需要完整查询的字符串，并在第二个参数上进行附加绑定(bind)。如果您愿意，您仍然可以首先使用照亮的查询构建器构建它，然后使用生成的字符串运行选择。

$query = DB::query()
    ->select('CC AS CountOfVisits', DB::raw('count(CC) AS Users'))
    ->fromSub(function (\Illuminate\Database\Query\Builder $query) {
        $query->select('user_id', DB::raw('count(user_id) AS CC '))
            ->from('mytable')
            ->groupBy('user_id');
    }, 'CC')
    ->groupBy('CC');

$result = DB::connection()->select($query->toSql());