这是我的 MySQL 查询(在 phpMyAdmin 中工作):
SELECT waktu_kerusakan, workcenter, COUNT(workcenter) AS jumlah_repair
FROM repair WHERE year(waktu_kerusakan)='2019' GROUP BY workcenter ,
month(waktu_kerusakan) BETWEEN 1 and 6 Order By jumlah_repair Desc
然后,我尝试像下面这样使用 Laravel 语法(不起作用):
$sql = Main::groupBy('workcenter')->select('workcenter', \DB::raw('count(*) as frekuensi'))
->whereYear('waktu_kerusakan', 'like', "%".$tahun."%")
->OrderBy('frekuensi', 'Desc')
->groupBy(\DB::raw("MONTH(waktu_kerusakan)"), [1, 6])
->get();
请任何人帮助我将 MySQL 查询转换为 Laravel 语法。谢谢!
最佳答案
试试这个。
$repair = DB::table('repair')
->select('waktu_kerusakan','workcenter', DB::raw('COUNT(workcenter) AS jumlah_repair'))
->whereYear('waktu_kerusakan', $tahun)
->groupBy(DB::raw("MONTH(waktu_kerusakan)"), 'workcenter')
->whereIn(DB::raw('MONTH("waktu_kerusakan")'),[1, 6])
->orderBy('frekuensi', 'DESC')
->get()
关于mysql - 如何将此 SQL 查询转换为 Laravel 语法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58741452/