php - 如何将 mysql 数组传递给 jquery php

Question

我有一个 PHP 文件，它从数据库表获取数据并将其发送到 jQuery AJAX:

include '../../Connections/Base.php';   

$query = "SELECT codemeli,name,family FROM members ORDER BY id ASC";

if ($result = $mysqli->query($query)) {
    while ($row = $result->fetch_assoc()) {

        echo  json_encode($row);  
    }
} else {
    echo $mysqli->error;
}

jQuery 代码是:

$("#generate").click(function() {
    $.ajax({
        type: 'POST',
        url: "postpon/signup/showMeliCode.php",
        success: function (response) {
            alert("Before Parse");  // It's work
            response = $.parseJSON(response); // don't work
            alert(responde);   // don't work
        }
    })

})

如您所知，$.parseJSON 不起作用。 为什么 parseJSON 不起作用？

Answer 1

首先，$.parseJSON已弃用。

As of jQuery 3.0, $.parseJSON is deprecated. To parse JSON strings use the native JSON.parse method instead.

您需要输出结果集，而不是单独输出行:

include '../../Connections/Base.php';   

$query = "SELECT codemeli,name,family FROM members ORDER BY id ASC";

if ($result = $mysqli->query($query)) {
    echo json_encode($result->fetch_all(MYSQLI_ASSOC));
} else {
    echo json_encode(['success' => false, 'message' => $mysqli->error]);
}

$("#generate").click(function() {
    $.ajax({
        type: 'POST',
        url: 'postpon/signup/showMeliCode.php',
        contentType: 'application/json; charset=utf-8',
        success: function (response) {
            console.log(response);
        }
    });
});