Php foreach 在时隙间隔中循环，如果间隔空闲则仅返回四分之一时间

Question

我有一个 mySQL 表“timeslots”，其中包含“intervals”和“reserved”列。我如何循环遍历它并仅返回 15 分钟的间隔，但必须保留“剪切”15 分钟的间隔 = 0。例如，我应该循环遍历“间隔”列并返回 08:15:00 但跳过08:00:00 因为 08:08:00 间隔被保留(保留列 = 1)，我也应该跳过间隔 08:45:00 因为 08:53:00 被保留 = 1。我已附上表格的图像对于这个问题。

我几天来一直在尝试寻找解决方案，但没有成功。

public function getTimeSlots($app)
{
$timeslots = Timeslot::where('app', '=', $app)->where('reserved', '=', 0)->orderBy('intervals', 'ASC')->get();
    $timeslotlist = array();

    foreach ($timeslots as $timeSlot) {

        $timeslotlist[] = array(
            'id' => $timeSlot['id'],
            'app' => $timeSlot['app'],
            'intervals' => $timeSlot['intervals'],
            'reserved' => $timeSlot['reserved'],
        );
    }
   return json_encode($timeslotlist);
}

Answer 1

您首先需要获得预留的插槽。然后在循环中检查该槽位是否有下一个保留槽位。

public function getTimeSlots($app)
{
$reservedSlots = Timeslot::where('app', '=', $app)->where('reserved', '=', 1)->orderBy('intervals', 'ASC')->get();
$timeslots = Timeslot::where('app', '=', $app)->where('reserved', '=', 0)->orderBy('intervals', 'ASC')->get();
    $timeslotlist = array();

    foreach ($timeslots as $timeSlot) {
        $haveNextReservedSlot = array_filter($reservedSlots, function($v) use($timeSlot){ 
             $start_date = new DateTime($timeSlot['date'].' '.$timeSlot['intervals']);
             $since_start = $start_date->diff(new DateTime($v['date'].' '.$v['intervals']));
             return $since_start->i < 15; //if difference less than 15 min
      });
        if($haveNextReservedSlot) continue;

        $timeslotlist[] = array(
            'id' => $timeSlot['id'],
            'app' => $timeSlot['app'],
            'intervals' => $timeSlot['intervals'],
            'reserved' => $timeSlot['reserved'],
        );
    }
   return json_encode($timeslotlist);
}