有逻辑的主要应用程序，我们将应用程序扩展到 Apple Watch。
添加目标后，xCode 创建了另外 2 个应用程序:带代码的扩展和 watch 套件应用程序。
问题:扩展中的代码如何重用现成的和已经制作好的主 iOS 应用程序的逻辑？扩展应用程序如何与主应用程序通信并发送命令。
最佳答案
要与包含的 iPhone 应用程序通信，您可以使用
(BOOL)openParentApplication:(NSDictionary *)userInfo
reply:(void (^)(NSDictionary *replyInfo,
NSError *error))reply
在你的WKInterfaceController
来自 Apple 文档
Use this method to communicate with your containing iOS app. Calling the method causes iOS to launch the app in the background (as needed) and call the
application:handleWatchKitExtensionRequest:reply: method of its app delegate. That method has the following signature:
- (void)application:(UIApplication *)application handleWatchKitExtensionRequest:(NSDictionary *)userInfo
reply:(void(^)(NSDictionary *replyInfo))reply
The app delegate receives the dictionary you pass into the userInfo parameter and uses it to process whatever request you made. If it provides a reply, WatchKit executes the block you provided in the reply parameter of this method.
关于ios - Apple Watch、WatchKit Extension 和主要应用程序，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27190949/