mysql - 用于一对多共享数据收集的 JPA 映射，具有用户特定值

Question

我有一个包含成就列表的用户模型

@Table(name = "user")
@Entity
@NamedEntityGraph(name = "User.achievements",
        attributeNodes={
                @NamedAttributeNode("achievements")
        })

@Data
public class User {
 @Id
    @NotNull
    @Column(name = "username")
    private String username;
    @Column(name = "password")
    private String password;

@ElementCollection(fetch = FetchType.LAZY, targetClass = Achievement.class)
private List<Achievement> achievements = new ArrayList<>();

}

这是成就模型

@Entity
@Data
@Table(name = "achievement")
public class Achievement {

@Id
@GeneratedValue(generator = "system-uuid")
@GenericGenerator(name = "system-uuid", strategy = "uuid")
private String achievementId;

@Column(name = "title")
private String title;

@Column(name = "description")
private String description;

@Column(name = "achieved", columnDefinition="BOOLEAN DEFAULT false", nullable = false)
private boolean achieved = false;

从@ElementCollection映射生成的user_achievements表，其中atm仅包含用户和成就外键

我希望将 bool 实现值移至user_achievements表，理想情况下无需创建单独的模型User_Achievements

我对使用 Jpa 相当陌生，但我觉得这个场景太基础了，所以必须有一个直接的方法来做到这一点，我似乎无法找到它

Answer 1

@Entity
class UserAchievement {

  @EmbeddableId
  UserAchievementId id;

  @ManyToOne(fetch=LAZY)
  @JoinColumn(name="user_username", insertable=false, updatable=false)
  User user;

  @ManyToOne(fetch=LAZY)
  @JoinColumn(name="achivement_achivement_id", insertable=false, updatable=false)
  Achivement achivement;

  // and other fields
}

class User {

  // ...

  @OneToMany(mappedBy="user")
  List<UserAchievement> userAchievements;
}

并且您需要定义UserAchievementId