mysql - 在 Mysql 中使用 join、sum 和 group by

Question

首先，我有 3 个表，表的名称是“users”、“references”和“operations”。

结构如下..

users
+----+------------+----------------+
| id | name       | referance_code |
+----+------------+----------------+
|  1 | Jack       | 11111111       |
|  2 | Rose       | 22222222       |
|  3 | Einstein   | 33333333       |
|  4 | Che        | 44444444       |
|  5 | Recep      | 55555555       |
+----+------------+----------------+

用户相互引用的中间表，
*如果在references表中注册的用户id也与users表中的id相关联，则users表中的reference code字段由references表中的“reference_user_id”字段绑定(bind)。

referances
+----+------------------+-------------------+
| id |register_user_id  | referance_user_id |
+----+------------------+-------------------+
|  1 | 2                | 11111111          |
|  2 | 3                | 11111111          |
|  3 | 4                | 22222222          |
|  4 | 5                | 33333333          |
|  5 | 6                | 44444444          |
+----+------------------+-------------------+

我最后一张交易表

transactions
+-----+--------------------+-------+-----------------------------+
| id  | amount   | user_id | type  | referance_register_user_id  |
+-----+----------+---------+-------+-----------------------------+
|  1  | +200      | 1       |  4    |          3                 |
|  2  | +200      | 1       |  8    |          2                 |
|  3  | -300      | 3       |  4    |          5                 |
|  4  | -400      | 4       |  4    |          3                 |
|  5  | -400      | 5       |  4    |          5                 |
|  6  | -500      | 1       |  6    |          3                 |
|  7  | -400      | 2       |  4    |          5                 |
|  8  | -300      | 3       |  4    |          5                 |
|  9  | -200      | 4       |  4    |          3                 |
|  10 | -400      | 5       |  3    |          5                 |
|  11 | -100      | 3       |  4    |          5                 |
|  12 | -300      | 2       |  4    |          5                 |
|  13 | -200      | 1       |  4    |          5                 |
|  14 | +300      | 1       |  4    |          2                 |
|  15 | +500      | 1       |  4    |          3                 |
+-----+-----------+---------+-------+----------------------------+

sql output
+-----------+--------+
| username  | amount |
+-----------+--------+
|  Rose     | 500    |
|  Einstein | 700    |
+-----------+--------+

我想为“Jack”用户写一个代码，首先连接到references表，然后用references表中的“register_user_id”连接到操作表并获取id，referenced_register_user，引用类型4和8，得到金额字段。

我希望输出是这样的

所以你自己的user_id from user_id = 1

类型 4 或 8

最后引用_注册_用户_id 2 AND 3

Answer 1

万一有人想看到它，我解决了这个问题，我在下面写的代码给出了我想要的输出

SELECT Sum(t.amount) AS amount, 
       r.register_user_id, 
       r.referance_user_id, 
       u.id          u_id, 
       u.username, 
       u.email, 
       t.amount, 
       t.user_id, 
       t.type, 
       t.referance_register_user_id 
FROM   referances r 
       LEFT JOIN users u 
              ON u.id = r.register_user_id 
       LEFT JOIN transactions t 
              ON r.register_user_id = t.referance_register_user_id 
WHERE  r.referance_user_id = '11111111' 
       AND user_id = '1' 
       AND ( t.type = 4 
              OR t.type = 8 ) 
GROUP  BY t.referance_register_user_id 
ORDER  BY amount DESC