PHP - 在 PHP 中比较分解的单词与 mysql varchar

Question

如何在 PHP 中比较分解的单词和 mysql varchar？
这段代码产生了我想要的，但它也给出了这个错误

veranderenwachtwoordjij
fatal error :在非对象上调用成员函数 fetch_assoc()......

$word = "Also, to be safe, change your password regularly... you don't have to be obsessive about it: every three hours or so should be enough. And because erring on the side of caution is always a good idea, fake your own suicide and change your identity at least once a year.";

$pieces = explode(" ", $word);

$x = 0;
while($x < word_count($word)) {  // word count function returns int (51)
  $aPiece = $pieces[$x]; // change $pieces[$x] to 'you' and then it works
  $result = $conn->query("SELECT * FROM dict WHERE english='$aPiece'");

  $z = 0;
  while($z < $num_result) // $num_result returns amount of rows in database
  {
    $row = $result->fetch_assoc(); //error line is here
    echo stripslashes($row['dutch']);
    $z++;
  }

  $x++;
}

Answer 1

我猜问题出在你的测试句子中的don:你忘记使用mysql_real_escape_string这样的函数转义引号。

例如:

$aPiece = mysql_real_escape_string($pieces[$x]);
$result = $conn->query("SELECT * FROM dict WHERE english='$aPiece'");