我在使用 mysql 时遇到了一个小问题。我有一组日期范围。例如:从 01-01-2011 到 01-06-2011 期间，此范围的价格为:每天 4500 美元。下一个日期范围从 01-07-2001 到 01-12-2011 开始，此范围的价格为:每天 300 美元
如果有人在前一天:05-04-2011 和 10-07-2011 之间注册了一天，我需要添加天数的价格。在这两个日期范围之间，价格有所不同。如何单独添加它们
这是我的表
谢谢
最佳答案
你可以做一个循环...
每次增加日期，然后查询该日期值落在哪个列..因此您可以插入相应的金额..
为此，您需要管理日期，例如一个月有多少天..如果年份发生变化，那么您还需要将月份设置为1..
我编写了一个代码....来显示日历。您可以相应地进行更改
$strt_date = '01-04-2011';
$end_date = '05-07-2011';
$date_array = array();
$date_array = explode('-',$strt_date);
$back_strt_date = $date_array[2]."-".$date_array[0]."-".$date_array[1];// YYYY-MM-DD
$front_strt_date = $date_array[1]."-".$date_array[0]."-".$date_array[2];// MM-DD-YYYY
$date_array = array();
$date_array = explode('-',$end_date);
$back_bk_date = $date_array[2]."-".$date_array[0]."-".$date_array[1]; // YYYY-MM-DD
$front_end_date = $date_array[1]."-".$date_array[0]."-".$date_array[2]; // MM-DD-YYYY
// fetching data for selected date interval
//$rs_couse_cnt = get_course_cnt($back_strt_date,$back_bk_date);
if($rs_couse_cnt =='No record Found'){
echo "No Records Found.";
exit;
}
// converting string in to TIMESTAMP
$sdate = strtotime($front_strt_date);
$edate = strtotime($front_end_date);
//getting starting and ending month of date...
$st_dt = array();
$en_dt = array();
// exploding date string in to array
$st_dt = explode('-',$strt_date);
$en_dt = explode('-',$end_date);
// assigning month value to variables...
$st_mon = $st_dt[0];
$en_mon = $en_dt[0];
// calculating month diff..
$mon_diff = $en_mon - $st_mon;
// assinging year value to variables....
$st_year = $st_dt[2];
$en_year = $en_dt[2];
//converting TIMESTAMP into desired date format...
$st_date = date('F jS Y',$sdate);
$en_date = date('F jS Y',$edate);
echo " <center><h2>$st_date - $en_date</h2></center>";
//echo " <br />start month is $st_mon & end month is $en_mon & month diff is $mon_diff";
//echo " <br />start year is $st_year & end year is $en_year";
$ttl_cnt =0;
for($i=$st_mon;($st_year<=$en_year);$i++){
$end = $en_mon+1;
if($i == $end && $st_year == $en_year){
break;
}
// this will continue until all months are completed
$st_mon_time_stamp = mktime(0,0,0,$i,1,$st_year);
echo "<br /><br /><center> <h3> ".date("F Y",$st_mon_time_stamp)."</h3></center>";
$no_of_days = date("t",$st_mon_time_stamp);
$str_cal ='<table border="1px" width="100%">
<thead>
<th>Sunday</th>
<th>Monday</th>
<th>Tuesday</th>
<th>Wednesday</th>
<th>Thursday</th>
<th>Friday</th>
<th>Saturday</th>
</thead>
<tbody>';
$cnt = 1;
$week = 0;
$mon_cnt = 0;
for($j=1;$j<=$no_of_days;$j++){
if($cnt >= $no_of_days){
break;
}
if($cnt == 1){
// for first row....
$time_stamp = mktime(0,0,0,$i,$cnt,$st_year);
$str_cal .='<tr>';
if(date("l",$time_stamp) == 'Sunday'){
$space = 0;
}
else if(date("l",$time_stamp) == 'Monday'){
$space = 1;
}
else if(date("l",$time_stamp) == 'Tuesday'){
$space = 2;
}
else if(date("l",$time_stamp) == 'Wednesday'){
$space = 3;
}
else if(date("l",$time_stamp) == 'Thursday'){
$space = 4;
}
else if(date("l",$time_stamp) == 'Friday'){
$space = 5;
}
else if(date("l",$time_stamp) == 'Saturday'){
$space = 6;
}
$dis = 7 - $space; //exit;
while($space != 0){
// this will display spaces in first row...
$str_cal .='<td> </td>';
$space--;
}
while($dis != 0){
// this will display calender date in first row...
if(strlen($i) == 1 && strlen($cnt)==1){
$date = $st_year.'-0'.$i.'-0'.$cnt;
}
else{
$date = $st_year.'-'.$i.'-'.$cnt;
}
$flg = 0;
for($rs=0;$rs<count($rs_couse_cnt);$rs++){
if($rs_couse_cnt[$rs]['EnrolledDate'] == $date){
$time_stmp = strtotime($date);
$str_cal .='<td>'.date('j S',$time_stmp).'<br /><br />Count : <a href="light_box_course.php" onClick="$.showAkModal(\'light_box_course.php?type=list&session_id='.$session_id.'&campus_id='.$campus_id.'&strt_date='.$rs_couse_cnt[$rs]['EnrolledDate'].'&end_date='.$rs_couse_cnt[$rs]['EnrolledDate'].'\',\'\',500,500);return false;">'.$rs_couse_cnt[$rs]['CourseCount'].'</a></td>';
$cnt++;
$mon_cnt += $rs_couse_cnt[$rs]['CourseCount'];
$flg = 1;
break;
}
}
if($flg == 0){
$time_stmp = strtotime($date);
$str_cal .='<td>'.date('j S',$time_stmp).'<br /><br /> </td>';
$cnt++;
}
$dis--;
}
$str_cal .='</tr>';
}
else{
// for rest of the rows...
$str_cal .='<tr>';
for($w=0;$w<7;$w++){
if($cnt<=$no_of_days){
if(strlen($i) == 1){
$date = $st_year.'-0'.$i.'-'.$cnt;
}
else{
$date = $st_year.'-'.$i.'-'.$cnt;
}
$flg = 0;
for($rs=0;$rs<count($rs_couse_cnt);$rs++){
if($rs_couse_cnt[$rs]['EnrolledDate'] == $date){
$time_stmp = strtotime($date);
$str_cal .='<td>'.date('j S',$time_stmp).'<br /><br />Count :<a href="light_box_course.php" onClick="$.showAkModal(\'light_box_course.php?type=list&session_id='.$session_id.'&campus_id='.$campus_id.'&strt_date='.$rs_couse_cnt[$rs]['EnrolledDate'].'&end_date='.$rs_couse_cnt[$rs]['EnrolledDate'].'\',\'\',500,500);return false;">'.$rs_couse_cnt[$rs]['CourseCount'].'</a></td>';
$flg = 1;
$cnt++;
$mon_cnt += $rs_couse_cnt[$rs]['CourseCount'];
break;
}
}
if($flg == 0){
$time_stmp = strtotime($date);
$str_cal .='<td>'.date('j S',$time_stmp).'<br /><br /> </td>';
$cnt++;
}
}
else{
$str_cal .='<td> </td>';
}
}
$str_cal .='</tr>';
}
}
$ttl_cnt += $mon_cnt;
if($mon_cnt != 0){
$str_cal .='<tr>
<td> Monthly Count :</td>
<td colspan="6"><a href="light_box_course.php" onClick="$.showAkModal(\'light_box_course.php?type=list&session_id='.$session_id.'&campus_id='.$campus_id.'&strt_date='.$st_year."-".(strlen($i)==1?"0".$i:$i)."-"."01".'&end_date='.$st_year."-".(strlen($i)==1?"0".$i:$i)."-".$no_of_days.'\',\'\',500,500);return false;">'.$mon_cnt.'</td>
</tr>';
}else{
$str_cal .='<tr>
<td> Monthly Count :</td>
<td colspan="6">'.$mon_cnt.'</td>
</tr>';
}
$str_cal .='</tbody>
</table>';
if($i == 12){
$i=0;
$st_year ++;
}
echo $str_cal;
}
?>
关于php - 如何在mysql中求和不同的值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6591741/