PHP 和 SQL : Function to insert and update tables not working

Question

我有一个简单的代码，其中创建和修改表，但表并没有创建开始，并且出现以下错误:

Undefined variable: price on line 28
Undefined variable: newbrand on line 28
Undefined variable: newprice on line 28

第 28 行:

$conexion-> modify("Mitsubishi",40000000,$price,$newbrand,$newprice);

完整代码:

<?php

class MyDataBase{
    private $link;

    public function __construct($server,$user,$password,$base){
        //Conectar
        $this->link = mysql_connect($server,$user,$password);
        mysql_select_db($base,$this->link);
        }

        public function insert($model,$brand,$price){
            mysql_query("INSERT INTO autos (model, brand, price) VALUES ($model,'$brand', $price)",$this->link);}

        public function modify($model,$brand,$price,$newbrand,$newprice){
            mysql_query("UPDATE 'crautos'.'autos' SET 'brand' = '$newbrand',
                        'price' = '$newprice' WHERE 'autos'.'model' =5 AND 'autos'.'brand' = '$brand' AND 'autos'.'price' ='$price' LIMIT 1" ,$this->link);}

        public function __destruct(){
        //desconectar
        }

}


$conexion = new MyDataBase ('localhost', 'root', '','crcars');
$conexion-> insert(05,"Ford",50000000);
$conexion-> modify("Mitsubishi",40000000,$price,$newbrand,$newprice);
?>

Answer 1

$conexion-> 修改("三菱",40000000,$price,$newbrand,$newprice);

您从未设置过 $price、$newbrand、$newprice 的值。而且你也没有逃避你的数据:

public function insert($model,$brand,$price){
    $model = mysql_real_escape_string($model);
    $brand = mysql_real_escape_string($brand);
    $price = (int)$price;
    mysql_query("INSERT INTO autos (model, brand, price) VALUES ('$model','$brand', $price)",$this->link);
}

与修改相同，您应该转义您的数据，请参阅:http://php.net/manual/fr/function.mysql-real-escape-string.php