php - 我的 PHP MySQL while 循环不返回结果

Question

<?php
$sqls = mysql_query("SELECT weight FROM $usertablestats")
or die ("Query failed: " . mysql_error() . " Actual query: " . $query);
$ct = mysql_query ("COUNT * '$sqls'");

if ($ct > 0) {
   while ($row = mysql_fetch_array($sqls));{
      $weight = $row["weight"];
      echo "C" . $weight;
    }}
else {
  echo "No stats found";
}
?>

即使表中有数据，也会输出“未找到统计信息”。

<?php
$sqls = mysql_query("SELECT weight FROM $usertablestats")
or die ("Query failed: " . mysql_error() . " Actual query: " . $query);
$ct = mysql_num_rows($sqls);

if ($ct > 0) {
   while ($row = mysql_fetch_array($sqls));{
      $weight = $row["weight"];
      echo "C" . $weight;
    }}
else {
  echo "No stats found";
}
?>

这不会返回任何内容。完全没有 echo 。

我已经检查过它是否可以通过使用来访问:

<?php
   $sqls = mysql_query("SELECT weight FROM $usertablestats")
   or die ("Query failed: " . mysql_error() . " Actual query: " . $query);

   $row = mysql_fetch_array($sqls);

   echo $row;
?>

它确实返回第一个条目。

Answer 1

while 中有分号:

while ($row = mysql_fetch_array($sqls));{
//should be
while ($row = mysql_fetch_array($sqls)){

这会引起问题吗