我试图让我的查询从assignments
表中按月和年对行进行分组,并计算leads
表中具有特定值的行数。它们链接在一起,因为 assignments
表有一个 id_lead
字段,它是 leads
中行的 id
> 表。
d_new
是网站为 newsite.com 的月份潜在客户分配的计数
d_subprime
将是网站不是 newsite.com 的当月潜在客户分配计数
这里是正在使用的表格:
`leads`
id (int)
website (varchar)
`assignments`
id_lead (int)
date_assigned (int)
这是我的查询,但不起作用:
SELECT
MONTHNAME(FROM_UNIXTIME(a.date_assigned)) as d_month,
YEAR(FROM_UNIXTIME(a.date_assigned)) as d_year,
(select COUNT(*) from leads where website='newsite.com' ) as d_new,
(select COUNT(*) from leads where website!='newsite.com') as d_subprime
FROM assignments as a
left join leads as l on (l.id = a.id_lead)
where id_dealership='$id_dealership2'
GROUP BY
d_month,
d_year
ORDER BY
d_year asc,
MONTH(FROM_UNIXTIME(a.date_assigned)) asc
$id_dealership
是一个变量,其中包含我试图查看其计数的经销商 ID。
任何帮助将不胜感激。
最佳答案
您可以将时间戳截断为几个月,并使用获得的值进行分组,然后从中导出必要的日期部分:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
…
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
…
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC
嗯,LAST_DAY()
并没有真正截断时间戳,但它确实将属于同一月份的所有值转换为相同的值,这基本上就是我们所需要的。
我想计数应该与您实际选择的行相关,这不是您的子查询。像这样的事情可能会做:
…
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
/* or: COUNT(d.website) - COUNT(NULLIF(d.website, 'newsite.com')) AS d_new */
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
…
这是包含所有提到的修改的完整查询:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
d_new,
d_subprime
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC
关于mysql - 按月和年分组,从另一个表中计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9699533/