我有一个信息数组，其中有多个我想要匹配和计数的名称，然后移动到一个表格 View ，就像您在消息应用程序上看到的那样。
我已经到了这个地步。我可以在哪里登录并查看我想要的内容，但根本找不到任何解决方案，可以从集合中提取该信息并将其相应地放入 tableview 中。
例子
- (void)directMessagesReceived:(NSArray *)messages forRequest:(NSString
*)connectionIdentifier{
for(NSDictionary *d in messages) {
// NSLog(@"See Direct Messageges Parsing Info: %@", d);
Tweet *tweetDic = [[Tweet alloc] initWithTweetDictionary:d];
//[directMessages addObject:tweetDic];
[tweetDic autorelease];
}
//[arayToScan addObject:[messages valueForKey:@"sender_screen_name"]];
[arayToScan addObjectsFromArray:messages];
[self checkForDuplicateIDs];
// NSLog(@"Same ScreenName Received: %@", arayToScan);
//[self.mainTableView reloadData];
NSLog(@"DM COUNT = %i",[directMessages count]);
[DSBezelActivityView removeViewAnimated:YES];
}
- (NSSet *)checkForDuplicateIDs {
//CHECK FOR DUPLICATES IN ARRAY
NSArray *allIDs = [arayToScan valueForKeyPath:@"sender_screen_name"];
NSArray *sortedIDs = [allIDs sortedArrayUsingSelector:@selector(compare:)];
NSString *previousID = nil;
duplicateIDs = [NSMutableSet set];
for (NSString *anID in sortedIDs) {
if ([previousID isEqualToString:anID]) {
[duplicateIDs addObject:anID];
}
previousID = anID;
}
//THEN REMOVE ANY DUPLICATES IN NEW ARRAY
NSCountedSet *countedSet = [NSCountedSet setWithArray:sortedIDs];
NSMutableArray *oneMess = [NSMutableArray arrayWithCapacity:[sortedIDs count]];
NSMutableArray *multipleMess = [NSMutableArray arrayWithCapacity:[sortedIDs count]];
for(id obj in countedSet) {
if([countedSet countForObject:obj] == 1) {
[oneMess addObject:obj];
}
for(id duplicatenames in countedSet) {
if ([countedSet countForObject:duplicatenames]>1) {
[multipleMess addObject:duplicatenames];
[countedSet countForObject:duplicatenames];
}
}
}
//NSLog(@"NSCountedSet = %@",[countedSet allObjects]);
//NSLog(@"NSCountedSet = %@",countedSet);
//NSLog(@"One Message = %@",oneMess);
// NSLog(@"Multiple Messages = %@",multipleMess);
//HERE I HAVE ORIGINAL ARRAY IN ALBETICAL ORDER
// NSLog(@"Messages Containing more then 1 = %@",sortedIDs);
//HERE I HAVE DUPLICATES IN ALBETICAL ORDER
// NSLog(@"Messages Containing more then 1 = %@",duplicateIDs);
//HERE I HAVE THE MESSAGES ONLY CONTAING 1
//NSLog(@"Messages Containing only 1 = %@",oneMess);
//NOW I WANT TO COUNT THE DUPLICATES TO PLACE AS A STRING IN CELL FOR # OF MESSAGES & #
OF ROW IN TBLVIEW
//NSLog(@"Duplicates count = %i",[duplicateIDs count]);
// NSLog(@"Messages Containing only count = %i",[oneMess count]);
//HERE I WOULD ADD BOTH ARRAYS AND SEND TO MY ARRAY BELOW WHICH IS USED FOR MY TBLVIEW
THIS INFO IS RETRIEVABLE WHAT I NEED IS THE # OF EACH DUPLICATE AS SEEN
//ARRAY *NEWARRAY INIT WITH OBJECTS ,ONEMESS, MULTIPLEMESS,
//ARRAY CUSTOM # OF EACH MULTIPLE MESSAGE TO SHOW IN TBLVIEW???
//THEN I CAN CONTINUE WITH THE BELOW METHOD TO RELOD THE TABLEVIEW
//[directMessages addObject:NEWARRAY];
//[self.mainTableView reloadData];
return [[duplicateIDs copy] autorelease];
}
这是日志...这种情况发生的次数与它计数的次数一样多，但我只是记录它以查看它是否正常工作。任何帮助将不胜感激
Counted = <NSCountedSet: 0x6d8cb80> (Nkapoor124 [33], iphonetechtips [3], jima6636 [4], pro1995 [2], iphone266 [2], eenofonn [1], iphoneMaster323 [3], FreeAppl3 [2], Bababooey13 [7], _CL1CK_ [5], _ToyVan_ [4], Nucleiosis [26], dracossaint [6], AlexInHouston [1], FlybriTn [7], iOSGraphix [1], deckedsg [5], 19est80 [3], JHackstar [2], barsoverbeats [7], anonomys209 [5], 87whitestallion [1], bAdGigabit [55], Sgt_Impacto [3], Nazaroth [2], K_Nitsua [1], MannyIphone [6], iphoneman76 [3])
最佳答案
在您的说明中，您询问了每个副本的数量(数量？)。你可以在下面的计数中得到。如果您正在寻找每个重复的次数(而不是每个重复的总次数)，那么这就是计数 - 每个重复 1 次。如果是计数 - 1 是 0，则没有重复项。
我认为您正在寻找 NSCountedSet countForObject 方法。
下面的示例......
NSArray *names = [NSArray arrayWithObjects:@"John", @"Jane", @"John", nil];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:names];
for (id item in set)
{
NSLog(@"Name=%@, Count=%lu", item, (unsigned long)[set countForObject:item]);
}
将输出:
2011-09-30 01:00:50.665 Craplet[7854:707] Name=Jane, Count=1
2011-09-30 01:00:50.679 Craplet[7854:707] Name=John, Count=2
关于iphone - NSCountedSet - 获取集合中的项目数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7605543/