php - mysql 类似带有逗号的值

Question

基本上，表格的设置是这样的:

+-----------+----------+-------------+
|   land    |   city   |  perimeter  |
+-----------+----------+-------------+
|  America  |  Kansas  |      1      |
|  Britain  |  Berlin  |      4      |
|  Japan    |  Tokyo   |      5      |
+-----------+----------+-------------+

我当前的查询:

$query = "SELECT land, city, perimeter FROM agents WHERE land LIKE ? OR city LIKE ? OR perimeter LIKE ?";
$params = array("%China%","%Kansas%","%6%");

此查询有效，它将返回 America,Kansas,1。但是，如果我的 params 等于:

$params = array("%China%","%Beijing,London,Kansas,Bali%","%6%");

这不会返回任何内容。如何在以逗号分隔的值中使用 LIKE 来至少匹配这些逗号分隔值中存在的一项。

Answer 1

使用REGEXP代替LIKE(更多信息请参见:http://dev.mysql.com/doc/refman/5.0/en/regexp.html)。

$query = "SELECT land, city, perimeter FROM agents
   WHERE land REGEXP ? OR city REGEXP ? OR perimeter REGEXP ?";
$params = array("^China$","^Beijing|London|Kansas|Bali$","^6$");