php - 组合两个 MySQL 查询？

Question

$query1 = 'select DATE_FORMAT(time, "%Y-%m-%d") as date,
        count(*) as phone_TotalPerDay
        from numrequest
        where id_usr = "'.$id_user.'"
        AND id_re ="'.$id_re.'"
        AND request="ph"
        group by id_usr, year(time), DAYOFYEAR(time)
        order by year(time) DESC, DAYOFYEAR(time) DESC';  


$query2 = 'select DATE_FORMAT(time, "%Y-%m-%d") as date,
        count(*) as fax_TotalPerDay
        from numrequest
        where id_usr = "'.$id_user.'"
        AND id_re ="'.$id_re.'"
        AND request="fx"
        group by id_usr, year(time), DAYOFYEAR(time)
        order by year(time) DESC, DAYOFYEAR(time) DESC';  

有没有办法结合这两个查询。我真的需要它们在一种资源中。 目前，每个都显示每天号码请求的数量。我想将它们组合起来，以便每个 date 都有 phone_TotalPerDay 和 fax_TotalPerDay。

Answer 1

您可以使用条件总和，例如

$query1 = 'select DATE_FORMAT(time, "%Y-%m-%d") as date,
    sum(if(request = "ph", 1, 0)) phone_TotalPerDay,
    sum(if(request = "fx", 1, 0)) fax_TotalPerDay
    from numrequest
    where id_usr = "'.$id_user.'"
    AND id_re ="'.$id_re.'"
    group by id_usr, year(time), DAYOFYEAR(time)
    order by year(time) DESC, DAYOFYEAR(time) DESC';

如果请求类型匹配，if 语句将返回 1，否则返回 0，因此对这些值求和可有效计算与此条件匹配的行，并且我已从 where 子句中删除了请求条件。